3 years ago

6f+f(f+2)+3 f*to the 2nd power-4f

Mathematics

1 answer:

EastWind [94]3 years ago

8 0

Answer:

the answer is f^2+8f+3^-4f

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Answer: 5x ( x - 5y )

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3 years ago

Absolute value x-2=12

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Absolute value would be x=14

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Principal- $900, interest rate ordinary- 4%, term (days)- 45. find the interest

kirill [66]

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3 years ago

Endpoint given the Midpoint: * The midpoint of RP is M(2, 4). If one of the end points is R(-1,7), find the coordinates of the o

marin [14]

Answer:

The coordinates of other point are: (5,1)

Step-by-step explanation:

Given coordinates are:

M(x,y) = (2,4)

R(x_1,x_2) = (-1,7)

We have to find the coordinates of other point (x2,y2)

The formula for mid-point is given by:

$M(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Putting the values we get

$(2,4) = (\frac{-1+x_2}{2}, \frac{7+y_2}{2})$

Putting respective elements equal

$\frac{-1+x_2}{2} = 2\\-1+x_2 = 2*2\\-1+x_2 = 4\\x_2 = 4+1\\x_2 = 5\\And\\\frac{7+y_2}{2} = 4\\7+y_2 = 4*2\\7+y_2 = 8\\y_2 = 8-7\\y_2 = 1$

Hence,

The coordinates of other point are: (5,1)

8 0

3 years ago

If the circumference is 3/2 pi what is the area

11111nata11111 [884]

Here is your answer

$\frac{9}{16} \pi \: {units}^{2}$

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

$2\pi \: r = \frac{3}{2}\pi$

$r = \frac{\frac{3}{2}\pi}{2\pi}$

$r = \frac{3}{4}$

Now,

$area = \pi {r}^{2}$

$= \pi \times { (\frac{3}{4}) }^{2}$

$= \frac{9}{16}\pi \: {unit}^{2}$

HOPE IT IS USEFUL

8 0

3 years ago

6f+f(f+2)+3 f*to the 2nd power-4f​

6f+f(f+2)+3 f*to the 2nd power-4f