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Ksju [112]
3 years ago
8

Bruce has a 16 ounces bottle of water that is 1/2 full. He drinks 1/5 of the water left in the bottle. How many ounces of water

are left in the bottle
Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer: 1.6 Ounces.

16/2 is 8.

8/5 is 1.6

You can check this by multiplying 1.6 times 5 then by 2,

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T-shirts are sold in packages of 4.The store’s 139 employees will each be given 5 t-shirts. How many packages will the store nee
Novosadov [1.4K]

Answer:

174 packages of t-shirts    PLEASE GIVE BRAINLIEST

Step-by-step explanation:

139 x 5 = 695 t-shirts are needed

695 ÷ 4 = 173.75

Since you have to purchase whole packages of t-shirts you will need to buy 174 packages of t-shirts.  174 x 4 = 696 t-shirts


174 packages

8 0
3 years ago
The pet store sells bags of pet food there are 4 bags of cat food one sixth of the bags of food are bags of cat food how many ba
jeka57 [31]
The answer is 4 1/6 because 4/1 + 1/6= 25/6 = 4 1/6.
4 0
3 years ago
Solve for b. 4b-3b+7= 10
Morgarella [4.7K]

b = 3

Step-by-step explanation:

4b - 3b + 7 = 10

Add similar terms :

4b - 3b = b \\ b + 7 = 10

Collect like terms and simplify

b = 10 - 7 \\ b = 3

7 0
3 years ago
Read 2 more answers
A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

4 0
3 years ago
4. Mr Vidal puts (c) gallons of gasoline in my car at a price of $1.98 per
BabaBlast [244]

Answer: 1.98c + 2.28z = 58.43

Step-by-step explanation:

.

7 0
3 years ago
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