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Ksju [112]
3 years ago
8

Bruce has a 16 ounces bottle of water that is 1/2 full. He drinks 1/5 of the water left in the bottle. How many ounces of water

are left in the bottle
Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer: 1.6 Ounces.

16/2 is 8.

8/5 is 1.6

You can check this by multiplying 1.6 times 5 then by 2,

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Which statement describes the graph of g(x) with respect to the graph of f(x)?
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The vertex of the two functions is in the same place, so there is no translation involved. Point (0, 4) on f(x) is point (0, 12) on g(x).

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    <span>It is stretched vertically by a factor of 3.</span>
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Solve 24x + 2y = 48 for x
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Isolate x.
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Divide by 24.
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A linear function has a slope of Negative StartFraction 7 Over 9 EndFraction and a y-intercept of 3. How does this function comp
Ede4ka [16]

The way that this linear function compares to y+11 is that It has the same slope and the same y-intercept.

<h3>What is a linear function?</h3>

This is the type of function that would produce a line when it is graphed out.

When we write out the equations in 1 and 2 we would see that they are basically the same type of equation. A linear equation is made up of the slope and the intercept.

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3 0
1 year ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
Janice is making a soup recipe that normally yields 8 servings. The recipe calls for 3 pounds of chicken and a certain number of
kondaur [170]

Answer:Janice needs 5 pounds of vegetables.

Step-by-step explanation:

5 0
3 years ago
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