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Galina-37 [17]
3 years ago
5

PLEASE HELP DONT LINK FILES

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

10 cm³

Step-by-step explanation:

I could have used Area = height×length×width, but I counted instead :)

When I counted, I got 30/3 cm³ which is 10 cm³

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y = 3

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Any equation of a line that is written as x = # (meaning x equaling whatever number) is vertical on the graph. Therefore, x = -1 is a vertical line. And since x equals -1, all the points on the graph must have an x-value of -1.

We need to find a line that is perpendicular to it - and what would be perpendicular to a vertical line would be a horizontal line. Horizontal lines are represented by the equation y = # (meaning y equaling whatever number). Whatever number is written there is the y-value of all the points the horizontal line intersects.

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We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

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Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

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Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

\longrightarrow x^2-8x - 4x +32=0\\

\longrightarrow x(x-8)-4(x-8)=0\\

\longrightarrow (x-8)(x-4)=0\\

Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow x - 8 = 0\\ \qquad x -4=0

\longrightarrow x = 8 \qquad x = 4

\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}

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