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3 years ago

Helppppppp meeeeeee I don’t understanddddd

Mathematics

1 answer:

scoundrel [369]3 years ago

5 0

Answer:

DF = 9.5

Step-by-step explanation:

Given 2 secants from an external point to the circle, then

The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is

DE × DF = DC × DB

5(5 + x) = 5(5 + 4.5) ← divide both sides by 5

5 + x = 5 + 4.5

5 + x = 9.5 ( subtract 5 from both sides )

x = 4.5

Then

DF = DE + EF = 5 + 4.5 = 9.5

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Setler [38]

Y + R + V = 42
but 4 YEARS AGO : (R-4) +(V-4) = Y

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3 years ago

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3 years ago

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What is the value of m in the equation 5m − 7 = 6m + 11? A.18 B. 1 C. −18 D.−1

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Hello there ^ _ ^

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Good luck!

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4 years ago

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27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8

Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

$27^x=9^{x-4}$

Note that

$27=3^3\\ \\9=3^2,$

then

$27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}$

Rewrite the equation as

$3^{3x}=3^{2(x-4)},$

then

$3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8$

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3 years ago

Find the first five terms of the recursive sequence an=-6an-1 where a1=4.5

grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

$a_n=-6a_{n-1}, a_1=4.5$

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

$a_2=-6a_1 \\ \implies \: a_2=-6 \times 4.5 = - 27$

When n=3, we get:

$a_3=-6a_2 \\ \implies \: a_3=-6 \times - 27 = 162$

When n=4, we get:

$a_4=-6a_3 \\ \implies \: a_4=-6 \times 162 = - 972$

When n=5, we get:

$a_5=-6a_4 \\ \implies \: a_5=-6 \times - 972 = 5832$

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

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4 years ago