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konstantin123 [22]
3 years ago
15

If the door to the library is at (2, 4), the door to the mall is at (8, 2), and one

Mathematics
1 answer:
guapka [62]3 years ago
5 0

Answer:

6 miles

Step-by-step explanation:

The distance formula is expressed as;

D = √(x2-x1)²+(y2-y1)²

D = √(2-4)²+(8-2)²

D = √(-2)²+(6)²

D = √4 + 36

AD = √40

AD = 6.32

Hence the approximate distance between the library  and the mall is 6 miles

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alexgriva [62]
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3 years ago
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3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0
Naya [18.7K]

Answer:

<h2>x = -2 or x = 5</h2>

Step-by-step explanation:

The quadratic formula of a quadratic equation

ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}

\text{If}\ b^2-4ac

We have:

x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5

5 0
3 years ago
What two numbers have a sum of 217 and a <br> difference of 85?
Setler [38]

Answer:

the two numbers are 151 and 66

Step-by-step explanation:

x+y =217

x-y = 85

add the two equations

x+y =217

x-y = 85

-------------

2x = 302

divide by 2

2x/2 = 302/2

x = 151

now find y

x+y =217

151+y =217

subtract 151 from each side

y = 217-151

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8 0
3 years ago
Yesterday, Michelle's Snack Shack went through 3 3/5 bottles of ketchup. If they used 1 3/10 times as much mustard as ketchup, h
Dima020 [189]
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4 0
3 years ago
The graph of a quadratic function having the form f(x) = ax? + bx + c passes
insens350 [35]

Answer:

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Step-by-step explanation:

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The first differences of these numbers are ...

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And the second difference is ...

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For a quadratic function, second differences are constant. This means the next first-difference will be ...

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The value of the function at x=-3 is -20.

_____

The attachment shows using a graphing calculator to do a quadratic regression on the given points. The graph can then be used to find the point of interest. There are algebraic ways to do this, too, but they are somewhat more complicated than the 5 addition/subtraction operations we needed to find the solution. (Had the required x-value been different, we might have chosen a different approach.)

5 0
3 years ago
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