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REY [17]
3 years ago
9

A rabbit moves n times as fast as a squirrel . A fox moves m times as fast as a rabbit . The fox moves how many times as fast as

the squirrel?
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

the fox moves mn times as fast as the squirrel

Step-by-step explanation:

the easiest way to do problems like this is by using hypothetical values that make sense (it's best to avoid 0, 1, and 2)

we'll say that n = 3 and m = 4

so if the squirrel moves at <em>s</em> pace, then the rabbit moves at <em>ns</em>, or <em>3s.</em>

if the fox moves at m (4) times the rabbit's pace (3s), then it moves at <em>4(3s)</em>

then just switch out the numbers for their variables, giving you <em>m(ns) </em>

remember that s simply represents the squirrel's pace, we cannot replace it with a number in this case, so switch it with the idea/value it represents

and there you go, mn times the squirrel's pace

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864,414 how many times greater is the value represented by the 4 in the thousands place than the value in the hundreds place?
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Rebekah put the bottom of a 12 foot ladder 5 feet from the side of a house what is the distance form the bottom of the house to
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Step-by-step explanation:

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7 0
3 years ago
Four points partition the directed line segment from A to B. • Point P partitions the directed line segment from A to B into a 3
Alecsey [184]

Answer:

S is closest to B.

Step-by-step explanation:

Given a directed line segment from point A to B.

Point P divides the line A to B in a ratio 3:4.

Point Q divides the line A to B in a ratio 4:3.

Point R divides the line A to B in a ratio 2:5.

Point S divides the line A to B in a ratio 5:2.

To find:

The point which is closest to the point B.

Solution:

Here, to find the point closest to B we need to find the distances PB, QB, RB and SB.

We can see the sum of ratio 3:4, 4:3, 2:5 and 5:2 is 7.

Let the distance between A and B be 7 units.

Now, the distances can be found easily.

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The point which has the minimum distance from point B, will be nearest to B.

We can clearly observe that SB is the minimum distance.

Therefore, <em>S is closest to B</em>.

4 0
3 years ago
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