4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2
This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4
To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)
If you multiply this as well you get the same answer I got with the addition
The Solution.
Representing the problem in a diagram, we have
By formula,
In this case,
Substituting these values in the formula above, we get
Clearing the bracket, we get
Dividing both sides by 2, we get
Therefore, the correct answer is option C.
Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
5
Step-by-step explanation:
the options are wrong....... k
