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2 years ago

Pls help me simplify

Mathematics

1 answer:

andreev551 [17]2 years ago

5 0

The answer is 5 I had this question before

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over the past ten years, the town's population doubled in size. the population is currently 12,000. what was the population ten

IceJOKER [234]

The population ten years ago was 6,000.

Because the population doubled you divide 12,000 by 2

12,000 / 2 = 6,000

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3 years ago

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Identify the type of sample and whether it is a biased or unbiased sampling method.

iris [78.8K]

Answer:

1. biased

2. unbiased

3. unbiased

4. biased

5. unbiased

Step-by-step explanation:

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2 years ago

2(3 x5-8)-4x2 (8-6+2)

4vir4ik [10]

Answer:

-18

Step-by-step explanation:

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3 years ago

If you know the rate of a water leak in gallons per hour, how can you find the number of hours it takes for 1 gallon to leak out

Evgen [1.6K]

1/the rate of leakage per hour

This will give you the time it takes for 1 gallon to leak out in hours.

For example, if something is leaking at the rate of 12 gallons per hour, it will take 1/12 of an hour for 1 gallon to leak out. ( or 5 min)

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3 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0

2 years ago