Answer:
We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;
t² = 39.2 × 2/9.81
From which we have;
The time it takes the snowball to reach the ground is approximately 2.83 seconds
Step-by-step explanation:
The height of the building from which the ball is dropped, h = 39.2 m
The equation of the dropped a snowball, is given as follows;
t² = 39.2 × 9.8
Using the From the equation of free fall, we have;
s = u·t + 1/2·g·t²
Where;
u = The initial velocity = 0 m/s
t = The time of flight
g = The acceleration due to gravity = 9.81 m/s²
Therefore, we get;
∴ s = The height from which the snowball is dropped = 39.2 m
Therefore, we get;
39.2 = 0×t + 1/2×9.81×t²
∴ t² = 39.2 × 2/9.81 ≈ 7.99
t = √(7.99) ≈ 2.83
The time it takes the snowball to reach the ground, t ≈ 2.83 s.
Answer:
First option.
Step-by-step explanation:
Use the formula y = mx + b.
Where m is the slope, and b is the y-intercept.
y = -2x + 3
The slope is -2. The y-intercept is (0, 3).
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You have to include a drawing that relates the distace between de towers and some angles.
I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.
This lets you calculate the distance between the towers, d, as
tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft
The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.
Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft
Answer: 366.29 ft
The cheetah runs 2 meters/sec faster than the gazelle. Eventually the cheetah will overcome the gazelle. Since distance = rate times time, time = distance/rate.
Thus,
300 meters / (2 meters/sec) = 150 sec = 2 min 30 sec
