Answer:
y = 2x^2 is a parabola opening up with it's vertex at (0,0)... y=3x^2 -4 is also a parabola opening up, but it is 'thinner' in that it rises in y faster and it's vertex is at (0,-4)
Step-by-step explanation:
all equations of the type y = ax^2 + b are parabolas centered on the y-axis, soo the vertex is always on (0,b)
If a is positive then the parabola opens up,
the bigger a is, the 'thinner' the graph is, i.e. the faster the graph rises
the value of b determines the location of the vertex, if b is added, then the vertex rises over the x-axis, if b is subtracted then the vertex is below the x-axis
A' (3(-5),3(-4))= (-15,-12)
B' (3(2),3(6))=(6,18)
C'(3(4),3(-3))=(12,-9)
Ur answer is 2,1 and ur other one is 2,2
