Answer:
A = 219
C = 362
Step-by-step explanation:
Given,
581 = C + A
and
$1090.50 = 1.5C + 2.5A
solve 1st for A
A =581 - C
substute into 2nd
1090.50 = 1.5C + 2.5(581 - C)
solve for C
1090.50 = 1.5C + 1452.50 - 2.5C
1090.50 = -C + 1452.50
1090.50 - 1452.50 = -C
-362 = -C
C = 362
then
581 = C + A
581 = 362 + A
219 = A
A = 219
Answer:
There are a total of 23 cars with air conditioning and automatic transmission but not power steering
Step-by-step explanation:
Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.
Remember that for 2 sets E and F, we have that

Also,
|E| = |E ∩F| + |E∩F^c|
We now alredy the following:
|A| = 89
|B| = 99
|C| = 74

|(A \cup B \cup C)^c| = 24
|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).
|B \ (AUC)| = 65
|C \ (AUB)| = 26

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things
For example:
99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|
Therefore, |B∩C^c| = 99-11 = 88
And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.
This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.
Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2) / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B ) - correct
I believe the correct answer is 3×13^4+2×15^4=total area
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form
or 
Part 1) y varies inversely with x. If y = 8 and k (the constant of variation) = 19, what is x?
we know that

substitute the given values and solve for x



Part 2) y varies inversely with x, and k (the constant of variation) = 23. What is the value of y when x = 7?
we know that

substitute the given values and solve for y



Part 3) y varies inversely with x. When y = 6.7, x = 1. What is the value of k, the constant of inverse variation?
we know that

substitute the given values and solve for k

