Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Simple...
as far as I can see it looks like you need two names for the angle formed..-->>
the angle would be acute
and
complementary
Meaning both those angles <DHR and <DHM have to be both smaller than 90° but when you add them both they should equal 90°.
Thus, your answer.
Answer:
y = -4x + 4
Step-by-step explanation:
8x+2y+2=0
turn that into slope intercept form:
y = -4x - 1
a parallel line has the same slope, but different y-intercept
y = -4x + b
put (2,-4) into the equation
-4 = -4(2) + b
you get b=4
final product:
y = -4x + 4
Answer:
399.84
Step-by-step explanation:
408.00 x .98 (2% reduction from 100) = 399.84
