Answer:
<h2>
![\bold{a_7=33x-15}](https://tex.z-dn.net/?f=%5Cbold%7Ba_7%3D33x-15%7D)
</h2>
Step-by-step explanation:
In arithmetic sequence: a₂ - a₁ = a₃ - a₂ {common difference}
![a_1=5x+9\\a_2=8x+5\\a_3=11x+1\\\\\\d=8x+5-(5x+9)=8x+5-5x-9=3x-4\\\\a_n=a_1+d(n-1)\\\\a_7=5x+9+(3x-4)\cdot6\\\\a_7=5x+9+18x-24\\\\a_7=33x-15](https://tex.z-dn.net/?f=a_1%3D5x%2B9%5C%5Ca_2%3D8x%2B5%5C%5Ca_3%3D11x%2B1%5C%5C%5C%5C%5C%5Cd%3D8x%2B5-%285x%2B9%29%3D8x%2B5-5x-9%3D3x-4%5C%5C%5C%5Ca_n%3Da_1%2Bd%28n-1%29%5C%5C%5C%5Ca_7%3D5x%2B9%2B%283x-4%29%5Ccdot6%5C%5C%5C%5Ca_7%3D5x%2B9%2B18x-24%5C%5C%5C%5Ca_7%3D33x-15)
Answer:
It would be 7701
Step-by-step explanation: hope this helps!
5h - 3 = 17
First, substitute h for 4 and the equation becomes 5(4)-3
Then, use PEMDAS (order of operations) to answer.
5 x 4 = 20
20 - 3 = 17
Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
![\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Vbu%3D70-ax%20%5C%5C%20Vbk%3D20%2Bax%20%5C%5C%20%5Ctext%7Bwhere%3A%7D%20%5C%5C%20a%3D0.05%20%5C%5C%20Vbu%3D70-0.05x%20%5C%5C%20Vbk%3D20%2B0.05x%20%5Cend%7Bgathered%7D)
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
Sorry I can not help u right now