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3 years ago

Which expression shows 48 + 36 written as a product of two factors?

Mathematics

2 answers:

notsponge [240]3 years ago

8 0

Answer:

12(4+3)

Step-by-step explanation:

Factor out all of the problems.

Starting with 4(12+4)

This means (4*12)+(4*4)

48+16 is the answer to this

this isn't 48 + 36

12(4+3) is next

12*4 = 48

12*3 = 36

48+36 = 48 + 36

Therefore 12(4+3) is your answer

hope that helps!

denis23 [38]3 years ago

4 0

I think the correct choice is B

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Write down the next two numbers in each of the following sequences. 40 POINTS

SIZIF [17.4K]

Answer:

Below in bold.

Step-by-step explanation:

a) 0.04, 0.1, 0.16

You add 0.06 to get the next term:

The next 2 are: 0.22, 0.28.

b) 3, 9, 27

You multiply by 3 to get next term

Next 2 are: 81, 243.

c) 0.3, 1/3, 11/30

1/3 - 0.3 = 1/30

11/30 - 1/3 = 1/30

So common difference = 1/30

The next 2 terms are 12/30 and 13/30

= 2/5 , 13/30.

7 0

1 year ago

Pls help n explain what to do

monitta

Answer:

Step-by-step explanation:

12*0.75=9

To find this do 9/12.

4*0.75=y

y=3

8 0

3 years ago

Read 2 more answers

A 5.00 L air sample has a pressure of 107 kPa at a temperature of -50C. If the temperature is raised to 102C and the volume expa

joja [24]

Answer:

129.9 kPa

Step-by-step explanation:

The relationship between temperature T, volume V and pressure P is given by the ideal gas equation which is given as

K = PV/T where K is a constant such that were there is a change of temperature T₁, volume V₁ and pressure P₁ to temperature T₂, volume V₂ and pressure P₂ then the relationship may be given

P₁V₁/T₁ = P₂V₂/T₂

where T is measured in ⁰K

T₁ = -50 + 273

= 223 ⁰K

T₂ = 102 + 273

= 379 ⁰K

5 × 107/223 = P₂ × 7/379

P₂ = 129.9 kPa

7 0

3 years ago

Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.

Allushta [10]

Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
$f_x=5yz=0\implies y=0\text{ or }z=0$
$f_y=5xz=0\implies x=0\text{ or }z=0$
$f_z=5xy=0\implies x=0\text{ or }y=0$

Taken together, we find that (0, 0, 0) appears to be the only critical point on $f$ within the ball. At this point, we have $f(0,0,0)=0$ .

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

$L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)$

with partial derivatives (set to 0)

$L_x=5yz+2\lambda x=0$
$L_y=5xz+2\lambda y=0$
$L_z=5xy+2\lambda z=0$
$L_\lambda=x^2+y^2+z^2-1=0$

We then observe that

$xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2$

So, ignoring the critical point we've already found at (0, 0, 0),

$5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}$
$5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}$
$5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}$

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of $\left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right)$ , at which points we get a value of either of $\pm\dfrac5{\sqrt3}$ , with the maximum being the positive value and the minimum being the negative one.

5 0

3 years ago

Nknjjhbvyugvtfituyjnjjjjjnnnnj

-Dominant- [34]

Answer:

indeed

Step-by-step explanation:

3 0

3 years ago