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hodyreva [135]
3 years ago
12

Solve the inequality. Show your work. 6y - 8 = 10

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0
You have to subtract 6y-8 and then multiply by 10 with your answer
aleksandr82 [10.1K]3 years ago
4 0
The letter Y equals 3 you times it by 6 which will equal to 18 subtract by 8 will equal 10
y=3 6x3=18-8=10
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the lateral area of a cylinder is 325 pi in2 the radius is 13 in find the following Volume. surface area 
Nesterboy [21]
Volume: 2112.5π
Surface Area: 663π

First, let's find the height of the cylinder. Using the formula for lateral surface area, 2*π*r*h:

2*π*13*h = 325π
(divide π by both sides)
26h = 325
h = 12.5 in.

Next, let's solve the surface area of the cylinder using the formula π*r²*h.

π * 13² * 12.5 = π * 169 * 12.5 = 2112.5π.

Next, let's solve the surface area using the formula 2πrh + 2πr².
 
(2 * π * 13 * 12.5) + (2 * π * 13²) = 325π + 338π = 663π.
5 0
4 years ago
What value must k take in order for the following expression to be greater than zero?
svetlana [45]

Basically anything greater than zero...k>0

8 0
3 years ago
What is angle LKM? I need help right away please!!
kykrilka [37]

Answer:

Angle LKM is 110

Step-by-step explanation:

Since all the angles in a triangle equal 180, and 60 is one angle you can see its an equilaterial triangle.

so x=60

Then 3(60)-70=110

So LKM=110

8 0
3 years ago
Read 2 more answers
In a fraternity with 40 members , 18 take mathematics, 5 take both mathematics and physics, and 8 take neither mathematics nor p
garri49 [273]

Answer: 14 members take physics but not mathematics

Step-by-step explanation:

Please see the attached for a diagrammatic representation of this situation.

Since there are 40 members but 8 did not offer any of mathematics or physics, then:-

40 - 8 = 32

So, 32 members of the fraternity offer maths, physics or both.

5 members offer both mathematics and physics .

Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5

Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)

Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.

Therefore, (18 - 5) + 5 + (P - 5) = 32

18 - 5 + 5 + P - 5 = 32

18 + P - 5 = 32

P + 13 = 32

P = 32 - 13

P = 19

19 members offered physics out of the 32 members that offered maths, physics or both.

To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics

19 - 5 = 14

Therefore, 14 members of the fraternity offer only physics

5 0
3 years ago
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4 bc of the words you know
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