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3 years ago

I need help my math teacher is bugging me to answer the question for a day assignment

Mathematics

2 answers:

Makovka662 [10]3 years ago

7 0

Answer:

Hello! Mizuki here to save you from your math teacher!

The correct answer will be -6

Step-by-step explanation:

-1 x 2 x 3 = -2 x 3 = -6

Delvig [45]3 years ago

5 0

Answer:

-6

Step-by-step explanation:

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What are the answers?

Ber [7]

Answer:

y=6

RS= 47

ST= 22

RT= 69

Step-by-step explanation:

8 0

4 years ago

CORRECT + BEST EXPLANATION WILL GET BRAINLIEST (25 POINTS)

malfutka [58]

The answer is 60.26

triangle a=44 b=60.26 c=44.92

8 0

3 years ago

Does anyone know this answer?

d1i1m1o1n [39]

Answer:

it might be c

Step-by-step explanation:

or d hope this helps

5 0

4 years ago

NEED ANSWER ASAP - 100 POINTS

Zina [86]

<h2>Using the quadratic formula</h2>

The quadratic formula can help us solve for x in a quadratic equation:

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$

We can use this when the given equation is organized in standard form: $ax^2+bx+c=0$

<h3>Applying this to the problem</h3>

$2x^2+5x-4=0$

First we can identify the values of a, b and c:

a = 2

b = 5

c = -4

Plug these values into the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-5 \pm \sqrt{5^2-4(2)(-4)}}{2(2)}$

$x=\dfrac{-5 \pm \sqrt{25+32}}{4}$

$x=\dfrac{-5 \pm \sqrt{57}}{4}$

<h2>Answer</h2>

Therefore, the two possible values of x are:

$x=\dfrac{-5 +\sqrt{57}}{4}$

$x=\dfrac{-5 -\sqrt{57}}{4}$

3 0

3 years ago

Someone please help me

lina2011 [118]

Answer:

$\displaystyle \boxed{\frac{60}{61}} = cos\:θ_1$

Step-by-step explanation:

$\displaystyle arcsin\: \frac{11}{61} ≈ 0,1813197744 \\ \\ cos\:0,1813197744 ≈ \frac{60}{61}$

Since this answer is in Quadrant I, this would be a positive-positive answer, which in this case, will remain a positive.

Extended Information on Quadrants

$\displaystyle Positive-Negative → Quadrant\:IIII \\ Negative-Negative → Quadrant\:III \\ Negative-Positive → Quadrant\:II \\ Positive-Positive → Quadrant\:I \\ \\$

Extended Information on Trigonometric Ratio Values

$\displaystyle y-values → sin\:θ \\ x-values → cos\:θ$

I am joyous to assist you anytime.

5 0

4 years ago