The form is y = kx
Replace y and x:
50 = k(5)
Solve for k by dividing both sides by 5
K = 10
Answer:
6T + p
6T + p = 27
T = 4 ; p = 4
Step-by-step explanation:
Given the following :
Points awarded for touchdown = 6 and then try for a point 'p' after touchdown
Hence, number of points scored on
touchdowns T and points after touchdowns p by one team in a game.
6points * number of touch downs (T) + point 'p' after touchdown
= 6T + p
B) If a team wins a football game 27-0,
Possible number of touch downs and points after touchdown :
Then 6T + p = 27
27 / 6 = 4 remainder 3
Hence, possible number of touch downs = 4
Number of points p = 27 - (6*4) = 27 - 24 = 3
C.) if winning = 21-7
Team A = 21
Hence, T = 21/6 = 3 remainder 3
T = 3 ; p = 3
Team B = 7
T = 7/6 = 1 remainder 3
T = 1 ; p = 1
Hence,
Total for both teams :
T = (1 + 3) = 4
p = (3 + 1) = 4
Solve for x. Show each step of the solution.
4(8 – x) + 36 = 102 – 2(3x + 24)
Solve the inequality for x. Show each step of the solution.
12x >9(2x- 3) - 15
