Ask question

Ask question

All categories

4 years ago

15

The scale on a map is 1cm for every 400 km. If Maine and Japan are 22cm apart on the map, what is the distance between Maine and

Japan? Please help!!!!!

1 answer:

Vsevolod [243]4 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Simplify and express with POSITIVE indices <br><br> a^3*a^-4*a^5

valkas [14]

Answer:

hello :

a^4

Step-by-step explanation:

a^3*a^-4*a^5 = a^(3 - 4 +5) = a^4

5 0

3 years ago

On Monday a Farmer sold 25196 pounds of potatoes on tuesday he sold 18023pounds on Wednesday he sold some more potatoes in all h

arlik [135]

Answer:

<em>estimated sales on Wednesday is 19000 pounds.</em>

<em></em>

Step-by-step explanation:

On Monday, he sold 25196 pounds. Estimated to the nearest thousand that is 25000 pounds.

On Tuesday, he sold 18023 pounds. Estimated to the nearest thousand, that is 18000 pounds

Wednesday's sales is unknown. We designate as x

All in all he sold 62409. Estimated to the nearest thousand, that is 62000

The sales on Monday, plus sales on Tuesday, plus sales on Wednesday, must all sum up to the total sales.

25000 + 18000 + x = 62000

43000 + x = 62000

x = 62000 - 43000 = 19000

therefore <em>estimated sales on Wednesday is 19000 pounds.</em>

3 0

3 years ago

Find the zero of the function:<br> y= 11x^2+25x-24

Ann [662]

X=8/11,-3 is the answer to your question.

4 0

3 years ago

Solving for matrices

muminat

Answer:

D

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)$

Multiply the first row by 5, the second row by -3 and add these two rows:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)$

Subtract the third row from the second:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)$

Divide the third row by 6:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)$

Now multiply the third equation by 26 and add it to the second row:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)$

You get the system of three equations:

$\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.$

From the third equation

$z=\dfrac{90}{45}=2.$

Substitute z=2 into the second equation:

$-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.$

Now substitute z=2 and y=5 into the first equation:

$3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.$

The solution is (1,5,2)

4 0

3 years ago

Mrs. Johnson put 22,250 miles

Viefleur [7K]

The change in quantities can be represented as percentage

<em>The percentage decrease in miles driven is 34.83%</em>

The given parameters are:

$\mathbf{Initial = 22250}$

$\mathbf{Final = 14500}$

The percentage decrease is calculated as:

$\mathbf{\%Decrease = \frac{Final - Initial}{Initial} \times 100\%}$

Substitute known values

$\mathbf{\%Decrease = \frac{14500- 22250}{22250} \times 100\%}$

$\mathbf{\%Decrease = \frac{-7750}{22250} \times 100\%}$

$\mathbf{\%Decrease = \frac{-775000}{22250} \%}$

$\mathbf{\%Decrease = -34.83 \%}$

The negative sign implies that, the change represents a decrement.

Hence, the percentage decrease in miles driven is 34.83%

Read more about percentage change at:

brainly.com/question/14801224

7 0

3 years ago