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Mariulka [41]
3 years ago
5

Solve 4x^2 - 3 = 3x^2 + 13 by using square roots

Mathematics
2 answers:
Andreyy893 years ago
7 0
X=4, -4 I think! Hope that helps
mina [271]3 years ago
7 0

Answer:

x = - 4, x = 4

Step-by-step explanation:

4x^2 - 3 = 3x^2 + 13 \\  \\ 4x^2 - 3  -  3x^2  -  13 = 0 \\  \\ 4 {x}^{2}  - 3 {x}^{2}  - 16 = 0 \\  \\  {x}^{2}  - 16 = 0 \\  \\  {x}^{2}  -  {(4)}^{2}  = 0 \\  \\ (x + 4)(x - 4) = 0 \\  \\ x + 4 = 0 \:  \: or \:  \: x - 4 = 0 \\  \\ x =  - 4 \:  \: or \:  \: x = 4 \\  \\ x =  - 4, \:  \: 4

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To figure that you can just add in your head since its easy.

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When you work backwards you do the opposite of what you are doing, so if your adding the opposite would be subtracting, and if your multiplying than the opposite would be dividing.

So you could work it out like this:

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Read 2 more answers
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