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3 years ago

14

Which action will solve the equation? m−20=9 Subtract 9 from each side. Add 20 to each side. Subtract 20 from each side. Add 9 t

o each side.

1 answer:

djyliett [7]3 years ago

7 0

Answer:

m=29

Step-by-step explanation:

add 20 to both sides and that is what m equals

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The cost of one pound of peanuts is 60% of the cost of one pound of cashews. if one pound of cashews cost 2$, what is cost of on

Dafna11 [192]

Hello!

In order to find the cost of one pound of peanuts, we need to find 60% of two dollars. To do that, we convert 60% to a decimal, then multiply that to the cost of cashews, which is two dollars.

60 / 100 = 0.60

0.60 x $2.00 = $1.20

Therefore, the cost of one pound of peanuts is $1.20.

The cost of two pounds of peanuts can be found by multiply the cost of one pound of peanuts by two. Then, we add the cost of one pound of cashews, which is two dollars.

$1.20 · 2 = $2.40

$2.40 + $2.00 = $4.40

Therefore, the total cost of two pounds of peanuts and one pound of cashews is $4.40.

Question 1: $1.20

Question 2: $4.40

4 0

4 years ago

What is the volume of the cone to the nearest tenth?

saw5 [17]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=5\\
h=14
\end{cases}\implies V=\cfrac{\pi (5^2)(14)}{3}$

7 0

3 years ago

Read 2 more answers

A rocket is shot straight up into the air with an initial velocity of 500 ft per second and from a height of 20 feet above the g

iragen [17]

The height of the rocket above the ground after $t$ seconds is given by the equation : $H= -16t^2+Vt+h$ , where $V$ is the initial velocity and $h$ is the initial height.

Given that, $V= 500 ft/second$ and $h= 20 ft$

So, the equation will become: $H= -16t^2 +500t+20$

A) For finding the height of the rocket 3 seconds after the launch, we will <u>plug $t=3$ into the above equation</u>. So....

$H= -16(3)^2+500(3)+20\\ \\ H= -16(9)+1500+20\\ \\ H= -144+1500+20=1376$

So, the height of the rocket 3 seconds after the launch is 1376 feet.

B) When the rocket at a height of 400 feet, then <u>we will plug $H= 400$ </u>

$400=-16t^2+500t+20\\ \\ 16t^2-500t-20+400=0\\ \\ 16t^2-500t+380=0\\ \\ 4(4t^2-125t+95)=0\\ \\ 4t^2-125t+95=0$

Using quadratic formula, we will get......

$t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(95)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{14105}}{8}\\ \\ t= 30.4705... \\ and \\ t= 0.7794...$

So, after 0.7794...seconds and 30.4705...seconds the rocket is at a height of 400 feet above the ground.

C) The time duration that the rocket remains in the air means we need to find <u>the time taken by the rocket to reach the ground</u>. When it reaches the ground, then $H=0$ . So.....

$0=-16t^2+500t+20\\ \\ -4(4t^2-125t-5)=0\\ \\ 4t^2-125t-5=0$

Using <u>quadratic formula</u>, we will get.....

$t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(-5)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{15705}}{8}\\ \\ t=31.2899...\\ and\\ t= -0.0399...$

<em>(Negative value is ignored as time can't be in negative)</em>

So, the rocket will remain in the air for 31.2899... seconds.

5 0

4 years ago

Please help me fill in the blanks :)

guapka [62]

Answer:

Absolute value is the distance from numbers on a number line. The absolute value of -7 is 7 b/c it is 7 units from 0. The absolute value of 5 is 5 b/c it is 5 units from 0.

A negative number is a number that is negative. On a horizontal number line negative numbers are to the left.

A positive number is a number that is positive. On a horizontal number line positive numbers are to the right.

I don't understand the last paragraph though. Hope this helped :D

Step-by-step explanation:

4 0

3 years ago

Help me please .........:::

guajiro [1.7K]

I think it he can buy 6

6 0

3 years ago