All categories

3 years ago

Steps for this equation 6(3e-8)=5e+43

Mathematics

1 answer:

Usimov [2.4K]3 years ago

8 0

Answer:

e = 7

Step-by-step explanation:

Eliminate parentheses using the distributive property.

18e -48 = 5e +43

13e -48 = 43 . . . . . . . . subtract 5e from both sides

13e = 91 . . . . . . . . . . . . add 48 to both sides

e = 7 . . . . . . . . . . . . . . divide both sides by 13

_____

Comment on equation solving

If there are parentheses or fractions, it usually works well to eliminate those. The distributive property is used to eliminate parentheses. Fractions can be eliminated by multiplying the equation by the denominator. (We mean 'multiply both sides of the equation by the denominator'.) If you have excellent skill with arithmetic using fractions, you don't need to go to the trouble to eliminate them.

After the numbers in the equation are mainly integers or decimals, the next step is to look to see where the variable of interest is located. You want to do what it necessary to put all of the variable terms on one side of the equal sign, and everything else on the other side. The procedure generally is to decide what you don't want, and subtract that from both sides of the equation.

Finally, you divide by the coefficient of the variable, so the variable stands alone on one side of the equal sign. This shows you the solution.

You might be interested in

Hellllllp brainliest going to first right answer

Cloud [144]

Answer:

the store sells 108 pounds of mulch and 72 ponds of gravel

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

In ΔJKL, the measure of ∠L=90°, JL = 24, LK = 7, and KJ = 25. What is the value of the sine of ∠K to the nearest hundredth?

podryga [215]

Given:

Given that JKL is a right triangle.

The measure of ∠L is 90°

The length of JL = 24, LK = 7, and KJ = 25.

We need to determine the value of sine of ∠K.

Value of sin ∠K:

The value of sin ∠K can be determine using the trigonometric ratio.

Thus, we have;

$sin \ \theta=\frac{opp}{hyp}$

Substituting $\theta=K$ , the side opposite to angle K is JL and the hypotenuse is JK

Thus, we have;

$sin \ K=\frac{JL}{JK}$

Substituting JL = 24 and JK = 25, we get;

$sin \ K=\frac{24}{25}$

Simplifying, we get;

$sin \ K=0.96$

$K=sin^{-1}(0.96)$

$K=73.74^{\circ}$

Thus, the measure of sine of ∠K is 73.74°

6 0

3 years ago

Can to answer all 4 please?

Tasya [4]

1) A - yes, b - no, c - yes
2) false, true, false
3) 85p - 34%
xp - 66%
x = 165 - she has to read 165 more pages.
4) Sylvia earns 84/12 = 7$/hr
maximum she can earn is 7*15 = 105 $
she will earn 105$ if she works for 15 hours

5 0

3 years ago

Given that 7x – 2y = 30

weeeeeb [17]

Answer:

x=32/7

Step-by-step explanation:

7x-2(1)=30 Plug in 1 as y and simplify.

7x-2=30 Add 2 on both sides of the equation.

+2 +2

7x=32 Divide both sides of the equation by 7.

/7 /7

x=32/7

Hope this helps...have an amazing day (｡･∀･)ﾉﾞ

8 0

3 years ago

A mass oscillating up and down on the bottom of a spring can be modeled as harmonic motion. if they weight is displaced a maximu

snow_tiger [21]

9514 1404 393

Answer:

1.63 cm (across the centerline from release)

Step-by-step explanation:

If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...

h(t) = -7cos(2πt/4)

h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm

That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.

If it is released from above the resting position, it will be 1.63 cm below the resting position at t=1.15 seconds.

6 0

3 years ago