60,000 + 3,000 + 20 + 9
= 63,000 + 29
= 63,029.
Answer: 63,029
Hope this helps have A wonderful Christmas
Step-by-step explanation:
Let assume that the the two numbers are X and Y and that X is the large number.
According to the question,
X + Y = 53 .................. Equation 1
then, X = 11 + Y........... Equation 2
Substitute equation 2 into equation 1.
[11 + Y] + Y = 53
11 + 2Y = 53
2Y = 53 - 11 = 42
2Y = 42
Y = 42 / 2 = 21,
Therefore, Y = 21 [Small number].
According to equation 1,
X +Y = 53
X + 21 = 53
X = 53 - 21 = 32.
Therefore, X = 32 [Big number].
For part (a), you have


If

, then

.
If

, then

.
So,

For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.

In the remainder term, the denominator

can't be factorized into linear components with real coefficients, since the discriminant is negative

. However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.



Then you have


When

, you have



When

, you have



So, you could write

but that may or may not be considered acceptable by that webpage.
15x - 5(3x-7) = 14
15x - 15x+ 35 = 14
35 = 14 ...NOT TRUE
answer
NO solution
you got it correct
Hey there! I’m happy to help!
Let’s use the variable g to represent the girls. This ratio shows that there are twice as many boys as girls (boys=2g)We also see that there are 18 more boys that girls. Let’s set up an equation
g+18=2g
We subtract 18 from both sides
g=2g-18
We subtract 2g from both sides.
-g=-18
We divide both sides by -1
g=18
Therefore, there are eighteen girls.
I hope that this helps! Have a wonderful day!