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Aleks [24]
3 years ago
6

Sheila is 155 cm tall lilias height is 10 cm less than twice sheila's height. how tall is lilia?​

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0
Answer: 300 cm

Explanation:
Pay attention to the problem senetemce closely. “Lillias height is 10 cm LESS than TWICE Sheila’s height.

An expression to help solve this problem would be:

155 x 2 - 10

Solve it:
155 x 2 - 10 = 300

COMM.ENT ME IF U HAVE ANY QUESTIONS

A brainliest would be nice if I got it correct!!
-SpaceMarsh
KonstantinChe [14]3 years ago
4 0

Answer:

145 cm

Step-by-step explanation:

155 cm - 10 cm

145 cm

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What is 60,000+3,000+20+9 in standard form?
kenny6666 [7]

60,000 + 3,000 + 20 + 9

= 63,000 + 29

= 63,029.

Answer: 63,029

Hope this helps have A wonderful Christmas

Step-by-step explanation:

4 0
3 years ago
The sum of two numbers is 53 and the difference is 11. What are the numbers?
vaieri [72.5K]
Let assume that the the two numbers are X and Y and that X is the large number.
According to the question, 
X + Y = 53 .................. Equation 1
then,  X = 11 + Y........... Equation 2
Substitute equation 2 into equation 1.
[11 + Y] + Y = 53
11 + 2Y = 53
2Y = 53 - 11 = 42
2Y = 42
Y = 42 / 2 = 21,
Therefore, Y = 21 [Small number].
According to equation 1, 
X +Y = 53
X + 21 = 53
X = 53 - 21 = 32.
Therefore, X = 32 [Big number].



4 0
3 years ago
Write out the form of the partial fraction decomposition of the function. Do not determine the numerical values of the coefficie
Dvinal [7]
For part (a), you have

\dfrac x{x^2+x-6}=\dfrac x{(x+3)(x-2)}=\dfrac a{x+3}+\dfrac b{x-2}
x=a(x-2)+b(x+3)

If x=2, then 2=b(2-3)\implies b=-2.

If x=-3, then -3=a(-3-2)\implies a=\dfrac35.

So,

\dfrac x{x^2+x-6}=\dfrac 3{5(x+3)}-\dfrac 2{x-2}

For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.

\dfrac{x^2}{x^2+x+2}=\dfrac{x^2+x+2-x-2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}

In the remainder term, the denominator x^2+x+2 can't be factorized into linear components with real coefficients, since the discriminant is negative (1-4\times1\times2=-7). However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.

x^2+x+2=0\implies x=-\dfrac12\pm\dfrac{\sqrt7}2i
\implies x^2+x+2=\left(x-\left(-\dfrac12+\dfrac{\sqrt7}2i\right)\right)\left(x-\left(-\dfrac12-\dfrac{\sqrt7}2i\right)\right)
\implies x^2+x+2=\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)

Then you have

\dfrac{x+2}{x^2+x+2}=\dfrac a{x+\dfrac12-\dfrac{\sqrt7}2i}+\dfrac b{x+\dfrac12+\dfrac{\sqrt7}2i}
x+2=a\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)+b\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)

When x=-\dfrac12-\dfrac{\sqrt7}2i, you have

-\dfrac12-\dfrac{\sqrt7}2i+2=b\left(-\dfrac12-\dfrac{\sqrt7}2i+\dfrac12-\dfrac{\sqrt7}2i\right)
\dfrac32-\dfrac{\sqrt7}2i=-\sqrt7ib
b=\dfrac12+\dfrac3{2\sqrt7}i=\dfrac1{14}(7+3\sqrt7i)

When x=-\dfrac12+\dfrac{\sqrt7}2i, you have

-\dfrac12+\dfrac{\sqrt7}2i+2=a\left(-\dfrac12+\dfrac{\sqrt7}2i+\dfrac12+\dfrac{\sqrt7}2i\right)
\dfrac32+\dfrac{\sqrt7}2i=\sqrt7ia
a=\dfrac12-\dfrac3{2\sqrt7}i=\dfrac1{14}(7-3\sqrt7i)

So, you could write

\dfrac{x^2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}=1-\dfrac {7-3\sqrt7i}{14\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)}-\dfrac {7+3\sqrt7i}{14\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)}

but that may or may not be considered acceptable by that webpage.
5 0
3 years ago
Read 2 more answers
I need help fast...........
Gennadij [26K]
15x - 5(3x-7) = 14
15x - 15x+ 35 = 14
35 = 14 ...NOT TRUE

answer
NO solution

you got it correct
5 0
3 years ago
The ratio of boys to girls in a group is 2:1. If there are 18 more boys than girls, work out how many girls there are.
rusak2 [61]
Hey there! I’m happy to help!

Let’s use the variable g to represent the girls. This ratio shows that there are twice as many boys as girls (boys=2g)We also see that there are 18 more boys that girls. Let’s set up an equation

g+18=2g
We subtract 18 from both sides
g=2g-18
We subtract 2g from both sides.
-g=-18
We divide both sides by -1
g=18

Therefore, there are eighteen girls.

I hope that this helps! Have a wonderful day!
4 0
3 years ago
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