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Marat540 [252]
3 years ago
13

What is the distance between the point (10,12) and (-4,-36)

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
Well using distance formula

d \:  =  \sqrt{(x {}^{2} }  - x {}^{1} ) + (y {}^{2}  + y {}^{1} )
The answer I got was Distance = 45.9 what ever unit of measure it might ask for. Feel free to check my math just in case.
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N+2 would be the correct answer... i think!!!!!!!!!!!!

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At the beginning of the week, Naveen has 87 trading cards. On Monday, he gets 9 more. On Tuesday, he gives 16 away. On Wednesday
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What happens to an image when it is enlarged using scale factor between -1and1
adell [148]
I have done this question before but i can’t remember
6 0
3 years ago
Find the coordinates of the endpoint of the image?
ra1l [238]

Given:

The graph of a line segment.

The line segment AB translated by the following rule:

(x,y)\to (x+4,y-3)

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

(x,y)\to (x+4,y-3)

Using this rule, we get

A(-2,-3)\to A'(-2+4,-3-3)

A(-2,-3)\to A'(2,-6)

Similarly,

B(4,-1)\to B'(4+4,-1-3)

B(4,-1)\to B'(8,-4)

Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

5 0
2 years ago
Find the solutions to x² = 12.
Novosadov [1.4K]

Answer:

x = \pm 2\sqrt3

Step-by-step explanation:

Hello!

Let's use the square root property to solve this question

Solve:

  • x^2 = 12
  • \sqrt{x^2} = \sqrt{12}
  • x = \pm\sqrt{12}
  • x = \pm \sqrt{4 * 3}
  • x = \pm 2\sqrt3

The answer is option A: x = ±2√3

3 0
2 years ago
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