Question

What is the product? (4y − 3)(2y2 + 3y − 5)

Answer 1

(4y−3)(2y^2+3y−5)
=(4y+−3)(2y^2+3y+−5)

=(4y)(2y^2)+(4y)(3y)+(4y)(−5)+(−3)
(2y^2)+(−3)(3y)+(−3)(−5)

=8y^3+12y^2-20y-6y^2-9y+15

=8y^3+6y^2-29y+15