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2 years ago

Solve this Equation 6 = ___ - (-8)

Mathematics

1 answer:

Tcecarenko [31]2 years ago

4 0

Answer:

-2

Step-by-step explanation:

____ is x

Move the terms.

6=x+8

-x=8-6

Calculate

-x=2

Change the signs

x= -2

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a local pizzeria sold 65 pizzas yesterday.(a) the owner offers the employees a bonus if the number of pizza increased by 20 pers

BigorU [14]

Answer: 78 pizzas

Step-by-step explanation:

65/10=6.5=10%

6.5*2=13 pizzas=20%

65+13=78 pizzas

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3 years ago

Tim runs 3 miles every 45 minutes. At this rate, how long did it take Tim to run 18 miles?

geniusboy [140]

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3 years ago

Bananas are $.59 a pound what is the constant of proportionality

hichkok12 [17]

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3 years ago

Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e0.0205t,wh

svetoff [14.1K]

Answer: a) 236,000.

b) 2021

Step-by-step explanation:

Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by $p = 130e^{0.0205t}$ (1)

where t = 0 corresponds to 1980.

Then , for 2009

t= 2009-1980=29

a. ⇒The population of Phoenix in 2009 = $p = 130e^{0.0205(29)}$

$p = 130e^{0.5945}$

$p =130(1.81212465608)=235.57620529\approx236$

Hence, the population of Orlando in 2009 was about 236,000.

b) Substitute p= 300 in (1) , we get

$300 = 130e^{0.0205t}$

$2.3077= e^{0.0205t}$ (Divide both sides by 130)

Taking Natural log on both sides,

$\ln(2.3077) = 0.0205t\\\\\Rightarrow\ t=\dfrac{\ln(2.3077)}{0.0205}$

$t=\dfrac{0.836251357528}{0.0205}=40.7927491477\approx41$

Hence, The year Orlando will have a population of 300,000 =1980+41 =2021

6 0

3 years ago

The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa

horsena [70]

Answer:

7.2 years

Step-by-step explanation:

$f(t) =200(1 - 0.956e^{-0.18t})$

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

$148 =200(1 - 0.956e^{-0.18t})$

divide both sides by 200

$\frac{148}{200} = 1 - 0.956e^{-0.18t}$

Now subtract 1 from both sides

$-0.26= - 0.956e^{-0.18t}$

Divide both sides by -0.956

$\frac{0.26}{0.956} =e^{-0.18t}$

Now take ln on both sides

$\frac{0.26}{0.956} =e^{-0.18t}$

$ln(\frac{0.26}{0.956} )=-0.18tln(e)$

$ln(\frac{0.26}{0.956} )=-0.18t$

divide both sides by -0.18

t=7.2

So 7.2 years

5 0

3 years ago