3 years ago

1.an=n + 52.an-4n-13.an-2n24.an-5-2n5.an-3-5n

Mathematics

1 answer:

Elis [28]3 years ago

3 0

This is what I’m trying to figure out

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-4x + 11y = 15 X = 2y Solve using substitution X = Y=

Virty [35]

-4(2y)+11y=15, -8y+11y=3y=15: y=5

X=2(5)=10

To check your work -4(10)+11(5)=15
15=15

8 0

2 years ago

Consider the absolute value function f(x) = a[x]. Would the values of a produce a shrink or a stretch? So

Rom4ik [11]

Answer:

Shrink:

a=1/4

a=0.3

Stretch:

a=60

a=2.5

a=1.1

Step-by-step explanation:

7 0

3 years ago

−2/3a+1/8−1/6a−3/4 PLEASE HELP

prohojiy [21]

Answer:

Evaluate:

- $\frac{5a}{6}$ - $\frac{5}{8}$

Factor:

$\frac{5(-4a-3}{24}$

Step-by-step explanation:

6 0

3 years ago

Look at the imagine. Help asap.

Stella [2.4K]

2x-1 < x+3

5x-1 > 6-2x

x-5 < 0

solve the inequality for x.

x < 4

x > 1

X < 5

find the intersection

X ∑ {1,4}

Alternative form: {x I 1 < x < 4}

∑ indicates summation and is used as a shorthand notation for the sum of terms that follow a pattern. For example, the sum of the first 4 squared integers, 12+22+32+42, follows a simple pattern: each term is of the form i2, and we add up values from i=1 to i=4.

4 0

1 year ago

(m^-4/3)^1/4 divided by m^0 n^3/4(m^-3/2 n^2)

postnew [5]

$\frac{(m^{-\frac{4}{3}})^{\frac{1}{4}}}{m^{0}(m^{-\frac{3}{2}}n^{2})} = \frac{m^{-\frac{1}{3}}}{m^{-\frac{3}{2}}n^{2}} = \frac{m^{\frac{3}{2}}}{m^{\frac{1}{3}}n^{2}} = \frac{m^{\frac{7}{6}}}{n^{2}} = \frac{\sqrt[6]{m^{7}}}{n^{2}} = \frac{\sqrt[6]{m^{6} * m}}{n^{2}} = \frac{\sqrt[6]{m^{6}}\sqrt[6]{m}}{n^{2}} = \frac{m\sqrt[6]{m}}{n^{2}}$

6 0

3 years ago

1.an=n + 52.an-4n-13.an-2n24.an-5-2n5.an-3-5n​

1.an=n + 52.an-4n-13.an-2n24.an-5-2n5.an-3-5n