Answer:
ez, answer choice number 4
Step-by-step explanation:
y=-1/8x(this is the slope) -4(this is the y intercept
Average rate = [h(3) - h(0)]/(3 - 0)
h(3) = 300 - 16(3)^2 = 300 - 16(9) = 300 - 144 = 156
h(0) = 300 - 16(0)^2 = 300
average rate = (156 - 300)/3 = -144/3 = -48
Therefore, the object falls with an average rate of 48 ft/s during the first 3 seconds.
The correct answer is 3/2.
Slope = Rate Of Change
Slope Formula: y₂ - y₁ 5 - 2 3
-------------- = ---------- = -----
x₂ - x₁ 3 - 1 2
I hope that this helps you!
Btw, ₁ and ₂ are subscripts, they do not have anything to do with the actual working of the problem.
![10.6 \times \frac{10}{10} = \frac{106}{100} = \frac{53 \times 2}{50\times 2} \\\\ = \frac{53}{50} = \boxed{\bf{1 \frac{3}{50}}}](https://tex.z-dn.net/?f=10.6%20%5Ctimes%20%5Cfrac%7B10%7D%7B10%7D%20%3D%20%5Cfrac%7B106%7D%7B100%7D%20%3D%20%5Cfrac%7B53%20%5Ctimes%202%7D%7B50%5Ctimes%202%7D%20%5C%5C%5C%5C%20%3D%20%5Cfrac%7B53%7D%7B50%7D%20%3D%20%5Cboxed%7B%5Cbf%7B1%20%5Cfrac%7B3%7D%7B50%7D%7D%7D)
and 10.6 is already written as a decimal.
Answer:![8865=6000(1+\frac{5\times t}{100})](https://tex.z-dn.net/?f=8865%3D6000%281%2B%5Cfrac%7B5%5Ctimes%20t%7D%7B100%7D%29)
Step-by-step explanation:
Given
Liam deposited ![P=\$\ 6000](https://tex.z-dn.net/?f=P%3D%5C%24%5C%206000)
Rate of interest is ![R=5\ \%](https://tex.z-dn.net/?f=R%3D5%5C%20%5C%25)
If the amount after t years is ![A=\$\ 8865](https://tex.z-dn.net/?f=A%3D%5C%24%5C%208865)
Simple interest is given by
![S.I.=\dfrac{P\times R\times t}{100}](https://tex.z-dn.net/?f=S.I.%3D%5Cdfrac%7BP%5Ctimes%20R%5Ctimes%20t%7D%7B100%7D)
And amount is
![A=P+S.I.](https://tex.z-dn.net/?f=A%3DP%2BS.I.)
![A=P(1+\frac{R\times t}{100})](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7BR%5Ctimes%20t%7D%7B100%7D%29)
Substituting values we get
![8865=6000(1+\frac{5\times t}{100})](https://tex.z-dn.net/?f=8865%3D6000%281%2B%5Cfrac%7B5%5Ctimes%20t%7D%7B100%7D%29)
![1.4775=1+\frac{5\times t}{100}](https://tex.z-dn.net/?f=1.4775%3D1%2B%5Cfrac%7B5%5Ctimes%20t%7D%7B100%7D)
![0.4775\frac{5\times t}{100}](https://tex.z-dn.net/?f=0.4775%5Cfrac%7B5%5Ctimes%20t%7D%7B100%7D)
![5t=47.75](https://tex.z-dn.net/?f=5t%3D47.75)
![t=\frac{47.75}{5}=9.55\ years](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B47.75%7D%7B5%7D%3D9.55%5C%20years)