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Sindrei [870]
3 years ago
9

Write a positive or negative integer that represents the situation.

Mathematics
1 answer:
Deffense [45]3 years ago
3 0

Answer:

X hope it helps

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Amy purchased a prepaid phone card for $20 Long distance calls cost $.22 a minute using this card Amy use her card only wants to
kogti [31]

Answer:

24

Step-by-step explanation:

$20 - $14.72 = $5.28

$5.28 ÷ $0.22=24

5 0
3 years ago
What is the slope of a line that passes through points (-1, 4) and (4, 9)?
melamori03 [73]

The slope is (difference in 'y') divided by (difference in 'x') .

Difference in 'y' = (9 - 4) = 5

Difference in 'x' = (4 - [-1]) = 5

Slope = 5/5 = 1 .

(I don't think we need the pictures at all.)

 
3 0
3 years ago
Read 2 more answers
If 5 sips +4 gulps = 1 glass and 13 sips +7 gulps = 2 glasses, how many sips equal a gulp?
nataly862011 [7]

Answer:

3 sips equal a gulp

Step-by-step explanation:

we have

5sips+4gulps=1glass ----> equation A

13sips+7gulps=2glass

Divide by 2 both sides

6.5sips+3.5gulps=1glass ----> equation B

equate equation A and equation B

5sips+4gulps=6.5sips+3.5gulps

Group terms that contain the same variable

4gulps-3.5gulps=6.5sips-5sips

0.5gulps=1.5sips

gulps=(1.5/0.5)sips

gulps=3sips

therefore

3 sips equal a gulp

3 0
3 years ago
A new car is purchased for 20000 dollars. The value of the car depreciates at 12. 5% per year. What will the value of the car be
Georgia [21]

To solve the problem we need to know about depreciation.

<h2>Formula of Depreciation</h2>

The formula of depreciation is given as,

A = P(1-r)^t

where,

A is the value of an object after t years of time,

P is the value of the object at the beginning, and

r is the rate of depreciation.

The value of the car after 11 years is $4,603.81.

<h2>Explanation</h2>

Given to us

  • Cost of Car at the beginning, p = $20,000
  • Rate of depreciation, r = 12.5%
  • Time, t = 11 years

<h3>Value of the car after 11 years</h3>

Substituting the values in the formula of depreciation,

A = P(1-r)^t

Value of the car after 11 years = P(1-r)^n

                                                 = \$20,000(1-0.125)^{11}\\\\&#10;= \$20,000\times 0.23\\\\&#10;= \$4,603.822 \approx \$4,603.81

Hence, the value of the car after 11 years is $4,603.81.

Learn more about Depreciation:

brainly.com/question/3023490

8 0
3 years ago
PLZ Help!!!! what is m A. 23<br> B. 20 <br> C. 43 <br> D. 63
yan [13]
I believe its c also.
3 0
3 years ago
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