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Sindrei [870]
3 years ago
9

Write a positive or negative integer that represents the situation.

Mathematics
1 answer:
Deffense [45]3 years ago
3 0

Answer:

X hope it helps

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What is the upper bound and lower bound for 35.7
stepladder [879]

Answer:

tried.. sry if it is wrong...

Step-by-step explanation:

some examples for u..

Mark me the Brainliest..PLS

7 0
3 years ago
The midpoint of AB is M(2, 0) . If the coordinates of A are (7, - 2) what are the coordinates of B?
ELEN [110]

Answer: B = ( -3 , 2)

Step-by-step explanation:

You would use a mid point formular because you are trying to find the middle of a line . The midpoint formular is (X1 + X2 , Y1 + Y2 )  

                                                                 /2            /2

From the information given A is (7 , -2 )

If you fill it in it would be 7 + X , -2 + X

                                         /2         /2           =   (2 , 0 )

The only posible solution would be 7- 3 /2  , -2 + 2 / 2

Makeing B (-3, 2).

5 0
3 years ago
Show me how to solve .384-.3798
-Dominant- [34]

Answer:

0.0042

Step-by-step explanation:

0.3840

- 0.3798

‐--------------

0.0042

‐--------------

8 0
3 years ago
Derek wrote the following paragraph proof for the Vertical Angles Theorem:
Aneli [31]
The phrase that would complete the proof is this:
Angle 2 is equal to Angle 4.

Vertical angles are angles formed when two lines intersect each other. The angles that are opposite each other are equal by a series of supplementary, complementary, and transitive property proofs.
7 0
4 years ago
Read 2 more answers
Factor and simplify: 4a^2c^2(a^2-b^2+c^2)^2
Dvinal [7]
4a^2c^2(a^2-b^2+c^2)^2 First, solve the exponent around the quantity. Being that it's a power of a power, you would multiply all the exponents inside the parentheses by two. So, after that, it would be: 4a^2c^2(a^4-b^4+c^4) Then, you would multiply what's outside the parentheses with every term within the parentheses: (4a^6c^2)-(4a^2c^2b^4)+(4a^2c^6) Now, you think you can take it from here, or do you need me to keep going?
8 0
3 years ago
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