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Sindrei [870]
3 years ago
9

Write a positive or negative integer that represents the situation.

Mathematics
1 answer:
Deffense [45]3 years ago
3 0

Answer:

X hope it helps

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What is the area of the trapezoid? The diagram is not drawn to scale.
loris [4]

Answer:

Area of trapezoid = 21 cm²

Step-by-step explanation:

Given:

Length of rectangular shape = 4 cm

Width of rectangular shape = 3 cm

Base of triangle = 3 cm

Number of triangle = 3 cm

Find:

Area of trapezoid

Computation:

Area of trapezoid = Area of middle rectangle + Number of triangle[Area of triangle]

Area of trapezoid = [l x b] + 2[(1/2)(b)(h)]

Area of trapezoid = [4 x 3] + 2[(1/2)(3)(3)]

Area of trapezoid = 12 + 9

Area of trapezoid = 21 cm²

6 0
3 years ago
Three friends each create 4 bags of starter bread dough. After ten days, each of those four bags is then divided into four more
natta225 [31]

To begin, each of the friends have made 4 bags of dough. This gives 12 bags at the outset. After 10 days, all 12 bags are made into (4*12) bags, or 48 bags. After 20 days, the 48 bags are made into (48*4), or the required 192 bags. After 20 days, then, the friends have the needed 192 bags.


Read more on Brainly.com - brainly.com/question/728837#readmore

8 0
4 years ago
Evaluate 2^3 [(15-7)] (4 divided by 2)].
Vanyuwa [196]

2^3= 8

15-7= 8

4/2= 2

8 * 8 * 2

64 * 2

answer: 128

5 0
4 years ago
A person who is 64 inches tall has a shoulder width of 16 inches. Write an equation relating the height h to the width w. Find t
kicyunya [14]

Let the height of the person with shoulder width of 18.5 be = x

As given, A person who is 64 inches tall has a shoulder width of 16 inches.

So, we have to find the height when the shoulder width is 18.5 inches.

We can relate these two by ;

\frac{64}{16}=\frac{x}{18.5}

16x=64*18.5

16x=1184

x=74

Hence, the height of the person should be 74 inches.

4 0
3 years ago
Read 2 more answers
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
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