Answer:
the first one
Step-by-step explanation:
y = 3x/3
y = x
Answer:
y = 37/4
Step-by-step explanation:
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
For this problem, you need to substitute 4 in for your variable t. the original equation is S(t) and the one you need is S(4) -- in other words, evaluate this equation when t = 4.
S(4) = 9(4) - 4
S(4) = 36 - 4
S(4) = 32 is your answer.
