Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
I can tell you that is 50 cents for cantaloupe at that price....
So I think he'd have to charge $1.50. He'd get what he paid for back plus a dollar. If C= one cantaloupe ....it would look something like
p > $1.50c
BECAUSE 1.50 x 14 = 21 minus the 7 he paid would leave you with 14... on dollar per cantaloupe... so the price can be anything greater than $1.50
4.125 x 14 = 57.75
So 57.75 is the answer and I have to show my work
Answer:
Step-by-step explanation:
The second one I believe.
10(3+10с)
This expression has a common factor of 10