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Mumz [18]
2 years ago
13

Logan took out $23,400 in student loans to attend college at a compound interest rate of 5%. He deferred payments for two years.

What will be his loan balance at the end of the two-year deferment?
Mathematics
1 answer:
blagie [28]2 years ago
8 0

Answer:

$25,740

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 23400 × 0.05 × 2 = 2340

I = $ 2,340.00

The simple interest accumulated

on a principal of $ 23,400.00

at a rate of 5% per year

for 2 years is $ 2,340.00.

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In a bag containing 143 M&M candies, there are 52 brown, 39 orange, 20 yellow, and 17 red candies. The rest of the M&M’s
frozen [14]

Answer:

183.04%

Step-by-step explanation:

52+39+20+17=128

128/100 = %/143

128 x 143 = 18,304

18,304 divided by 100 = 183.04

5 0
3 years ago
Solve: 2 In 3 = In(x-4)
Alona [7]

\bf \begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf 2\ln(3)=\ln(x-4)\implies \ln(3^2)=\ln(x-4)\implies \ln(9)=\ln(x-4) \\\\\\ \log_e(9)=\log_e(x-4)\implies e^{\log_e(9)}=e^{\log_e(x-4)}\implies 9=x-4\implies \boxed{13=x}

5 0
2 years ago
Can anyone help me with this?
kobusy [5.1K]

Answer:

-37z

Step-by-step explanation:

3 0
3 years ago
URGENT!! PLEASE HELP!!!
olga55 [171]

Answer:

The correct option is B.

Step-by-step explanation:

The formula for amount after compound interest is

A=P(1+\frac{r}{n})^{nt}

Where P is principal, r is rate of interest, n is number of times interest compounded in a period, t is number of years.

It is given that Felix took out an unsubsidized student loan of $40,000 at a 3.6% APR, compounded monthly. The amount after 33 month is

A=40000(1+\frac{0.036}{12})^{33}=44156.1074

The amount after 33 month is $44156.1074. So, the new principle amount is $44156.1074.

The monthly payment  of $44156.1074 for 20 years is

m=\frac{P.V.(\fracr)}{1-(1+r)^{-n}}

Where, P.V. is present value, r is rate of interest and n is number of times interest compounded.

m=\frac{44156.1074(\frac{0.036}{12})}{1-(1+\frac{0.036}{12})^{-20\times 12}}

m=258.362447711

m\approx 258.36

Therefore the correct option is B.

9 0
3 years ago
1. In the number 0.08 the digit 8 is in the...<br> Tenths<br> Hundreds<br> Thousands
Marrrta [24]

Answer:

hundreds

Step-by-step explanation:

ITS IN THE HUNDREDS, 100 has two zeros and .08 has two decimal places

4 0
2 years ago
Read 2 more answers
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