Solve for b at the top And x at the bottom I’ll give 17 points

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

Answer:

b = -1

x = 1

Step-by-step explanation:

8 - (b - 2) = 11

subtract 8 from both sides

- (b - 2) = 3

distribute

-b + 2 = 3

subtract 2 from both sides

-b = 1

now, to make the b positive, we make the other side negative by multiplying.

b = -1

-2x+ 4 = 5 -3x

subtract 4 from both sides

-2x = 1 -3x

add 3x to both sides

1x = 1

divide by 1

x = 1

(hopefully this helps?)

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What is the difference x/x^2-16-3/x-4

kenny6666 [7]

General Idea:

When simplifying a rational expression, we need to do the below steps:

(i) Factor the Denominator of each fraction

(ii) Identify the Least Common Denominator (It is the product of prime factors involved with its highest exponent)

(iii) Identify and rewrite the equivalent fraction with the desired LCD.

(iv) Once the denominator are same, Combine the numerator.

Applying the concept:

What is the difference x/x^2-16-3/x-4

I assume that you mean to type the expression $\frac{x}{x^{2}-16} -\frac{3}{x-4}$

Step 1: Factoring $x^{2} -16$

$x^{2} -16=x^{2} -4^{2} =(x+4)(x-4)$

Step 2: Identifying the LCD, we get $(x+4)(x-4)$

Step 3: Rewriting the second fraction by multiplying x+4 on both top and bottom of second fraction so that we get the LCD.

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{x}{(x+4)(x-4)} -\frac{3*(x+4)}{(x-4)*(x+4)} Step 4: Combine like terms since the denominators are same[tex] \frac{x-3(x+4)}{(x+4)(x-4)} =\frac{x-3x-12}{(x+4)(x-4)}=\frac{-2x-12}{(x+4)(x-4)} =\frac{-2(x+6)}{(x+4)(x-4)}$