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3 years ago

MIDPOINT AND DISTANCE DUE TONIGHT NEED ASAP

Mathematics

1 answer:

Ugo [173]3 years ago

3 0

Answer:

1. B

2. E

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

$d = \sqrt{(11--7)^{2} + (-5-2) ^{2} }$

=19.31

0.5-(6-0.5), -2- (1--2)

0.5-5.5,-2-3

(-5,-5)

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3 years ago

The fence around a circular garden is 18 feet long. What is the area of the garden to the nearest square foot? Use 3.14 for pi.

Sidana [21]

Answer:

A = 26 ft²

Step-by-step explanation:

To find the area of a circle, use the formula A = πr²

We know π = 3.14 and C = 18.

Use the circumference to find "r". C = 2πr

C = 2πr

18 = 2(3.14)r

18 = 6.28r

r = 18/6.28 Exact answer

r ≈ 2.866 Rounded to three decimal places

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Substitute π = 3.14 and r = 2.866.

A = πr²

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A = 3.14(8.213956) Multiply

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Add the units back in.

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3 years ago

Trevor gets 10 heads when flipping a weighted coin 18 times. What is the experimental probability that the next flip will come u

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Answer:

5/9

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2 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

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3 years ago

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Answer:

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3 years ago