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adoni [48]
3 years ago
5

HELP pls which of the above solids has the larger surface area

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

B. solid B

Step-by-step explanation:

solid a surface area: 150

solid b surface area: 184

taurus [48]3 years ago
7 0

Answer:

mmmmm

Step-by-step explanation:

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the racing car took 1 he 10mins to complete the 200km if the car crossed the finish line at 3:06pm what time did it being​
Ray Of Light [21]

Answer:

1:56 pm

Step-by-step explanation:

1:56 because 3:06 - 10 = 2:56

2:56 - 1:00= 1:56

7 0
3 years ago
In a random sample of 75 individuals, 52 people said they prefer coffee to tea. 99.7% of the population mean is between what two
marshall27 [118]
Sample size, n = 75
Point estimate, p = 52/75 = 0.693
Z at 99.7% confidence interval ≈ 2.96

Population mean interval = p+/- Z*Sqrt [p(1-p)/n]

Substituting;
Population mean interval = 0.693 +/- 2.96*Sqrt [0.693(1-0.693)/75] = 0.693+/-0.158 = (0.535,0.851) or (53.5%,85.1%)
7 0
3 years ago
you buy a new mountain bike for $200. tha value of the bike decreases by 25% each year. how much is your bike worth after 3 year
Brilliant_brown [7]

Answer:84.375

Step-by-step explanation:

i mean if you by a bike for 200 hundread and every year it goes down by 25% you would just subtract 25 % 3 times ;)

8 0
2 years ago
Select the expression that is NOT equivalent to 2 × (3 + 6).
Vinvika [58]
A. 18
B. 18
C. 18
D. 24
4 0
2 years ago
Read 2 more answers
A factory produces some batteries daily. 7/8 of the batteries are packaged immediately. 2/3 of the
frozen [14]

Answer:

\[\frac{1}{24}\]

Step-by-step explanation:

Let the total number of batteries produced daily be represented by x.

7/8 of the batteries are packaged immediately.

So the total number of packaged batteries = \[\frac{7x}{8}\]

Remaining batteries = \[x-\frac{7x}{8}\]

= \[\frac{x}{8}\]

Two third of the remaining batteries are sent to charity.

So the total number of batteries sent to charity= \[\frac{2}{3} * \frac{x}{8}\]

= \[\frac{x}{12}\]

Remaining batteries are faulty.

So the total number of faulty batteries = \[\frac{x}{8} - \frac{x}{12}\]

= \[\frac{3x - 2x}{24}\]

= \[\frac{x}{24}\]

So the faction of batteries which are faulty =

= \[\frac{x}{24} \div x\]

= \[\frac{1}{24}\]

3 0
3 years ago
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