You mix 2/5

(-1,4) (2,2) find midpoint?

notsponge [240]

$\text{Hey there!}$

$\text{The midpoint formula is: }\dfrac{\mathsf{x_2+x_1}}{2}, \dfrac{\mathsf{y_2+y_1}}{2}$

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$\mathsf{x_1 = -1}\\\\\mathsf{x_2=2}\\\\\mathsf{y_1=4}\\\\\mathsf{y_2=2}$

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$\dfrac{2-1}{2}\\\\\mathsf{2-1 = 1}\\\\\mathsf{2=2}\\\\\\\mathsf{x = \dfrac{\mathsf{1}}{2}}$

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$\mathsf{\dfrac{4+2}{2}}\\\\\mathsf{4+2=6}\\\\\mathsf{2=2}\\\\\mathsf{\dfrac{6}{2}=3}\\\\\\\mathsf{y=3}$

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$\boxed{\boxed{\text{Thus,\ your\ answer\ is:\boxed{(\dfrac{1}{2\ },\ 3)}}}}\checkmark$

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$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

6 0

3 years ago

A major hurricane is a hurricane with wind speeds of 111 miles per hour or greater. During the 20th century the mean number of t

Bas_tet [7]

Answer:

a) 0.3293 = 32.93% probability that the number of major hurricane to strike U.S mainland in any any give year is exactly one.

b) 0.878 = 87.8% probability that the number of major hurricane to strike U.S mainland in any any give year is at most one.

c) 0.122 = 12.2% probability that the number of major hurricane to strike U.S mainland in any any give year is more than one.

Step-by-step explanation:

We have the mean during an interval, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

During the 20th century the mean number of the major hurricanes to strike U.S mainland per year was 0.6.

This means that $\mu = 0.6$

Find the probability that the number of major hurricane to strike U.S mainland in any any give year is:

a) Exactly one

This is P(X = 1). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-0.6}*0.6^{1}}{(1)!} = 0.3293$

0.3293 = 32.93% probability that the number of major hurricane to strike U.S mainland in any any give year is exactly one.

b) At most one

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.6}*0.6^{0}}{(0)!} = 0.5488$

$P(X = 1) = \frac{e^{-0.6}*0.6^{1}}{(1)!} = 0.3293$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.5488 + 0.3292 = 0.878$

0.878 = 87.8% probability that the number of major hurricane to strike U.S mainland in any any give year is at most one.

c) More than one

This is:

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.878 = 0.122$

0.122 = 12.2% probability that the number of major hurricane to strike U.S mainland in any any give year is more than one.

6 0

3 years ago

5:7 and 2:11 are in equal ratios? True OR False? *

balandron [24]

Answer: false

Step-by-step explanation:

7 0

3 years ago

On a school field trip, the school requires that there are 6 teachers for every 90 students. If 135 students attend the trip how

Paraphin [41]

Answer:

the answer is 9 teachers

Step-by-step explanation:

step one is 135-90=?

step two is if 1 teachers for 15 students

2 techers are for 30 students until you get to 135

4 0

3 years ago

Read 2 more answers

If someone bought 100 chocolate bars, and 5 sodas, and the 100 chocolate bars cost 100 dollars, and have to pay taxes, the total

MAXImum [283]

Not knowing the taxes the soda would be estimated to cost around 15$

3 0

3 years ago