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kozerog [31]
2 years ago
13

Factorise fully the following expression (am-an+bm-bn)​

Mathematics
2 answers:
Luda [366]2 years ago
5 0

Answer:

\small \sf \: ( m - n ) ( a + b )

Step-by-step explanation:

( am - an + bm - bn)

  • Do the grouping

= ( am - an ) + ( bm - bn )

  • Factor out a in the first and b in the second group

= a ( m - n ) + b ( m - n )

  • factor out common term m - n by using distributive property

= ( m - n ) ( a + b )

belka [17]2 years ago
3 0

Step-by-step explanation:

am-an+bm-bn

m(a+b)-n(a+b)

(m-n)(a-b)

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Assume EFG = JKL.

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<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

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