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3 years ago

15

Brennanhasalreadytaken17quizzesduringpastquarters,andheexpectstohave2quizzesduringeachweekofthisquarter.Howmanyweeksofschoolwill

Brennanhavetoattendthisquarterbeforehewillhavetakenatotalof25quizzes?

1 answer:

jeka943 years ago

8 0

Brennan will have to take 8 more quizzes to get to 25

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Which of these ordered pairs is a solution for this linear inequality 3y-2x<=6? A. (-4,2) B. (1,3) C. (2,-4) D. (2,4)

Usimov [2.4K]

Answer:

C

Step-by-step explanation:

3y-2x<=6

3(-4) - 2(2)<=6

-12-4<=6

-16<=6

4 0

3 years ago

Please hurry attachment below will Brainly if answer correctly 30 POINTS

Rzqust [24]

Put everything into a calculator to change to decimal form to make things easier:
27/5=5.4
5.36=5.36
5 3/5=5.6
33/6=5.5
So now in order to least to greatest it would be:
5.36, 27/5, 33/6, 5 3/5

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3 years ago

Eileen brought 8 roses for $45.50.Which is the best way to estimate the cost of one rose?

masya89 [10]

Answer:

50 divided by 8 is the best estimation. gives you 6.25

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3 years ago

Given the Arithmetic sequence A1,A2,A3,A4 53, 62, 71, 80 What is the value of A38?

Murrr4er [49]

Answer:

$A_{38} = 350$

Step-by-step explanation:

The 5th term of the arithmetic sequence is 53. We can write the equation:

$a + 4d = 53...(1)$

The 6th term of the arithmetic sequence is 62. We can write the equation:

$a + 5d = 62...(2)$

Subtract the first equation from the second one to get:

$5d - 4d = 62 - 53$

$d = 9$

The first term is

$a + 4(9) = 53$

$a + 36 = 53$

$a = 53 - 36$

$a = 17$

The 38th term of the sequence is given by:

$A_{38} = a + 37d$

$A_{38} = 17+ 37(9)$

$A_{38} = 350$

3 0

3 years ago

Read 2 more answers

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago