Answer: 
Step-by-step explanation:
Given: A cubic kilometer=
cubic centimeters
The volume of world’s oceans=
cubic kilometers of water.
⇒ The volume of world’s oceans=
cubic centimeters of water.
Volume of a bucket = 20,000 cubic centimeters of water.
The number of bucket-loads would it take to bucket out the world’s oceans

![\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20n%3D%5Cfrac%7B1.4%5Ctimes10%5E%7B9%2B15%7D%7D%7B0.2%5Ctimes10%5E5%7D......%5Ba%5En%5Ctimes%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%5CRightarrow%5C%20n%3D7%5Ctimes10%5E%7B24-5%7D.....%5B%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5CRightyarrow%5C%20n%3D7%5Ctimes10%5E%7B19%7D)
hence,
bucketloads would it take to bucket out the world’s oceans.
Answer:
Sum of the sequence (Sn) = 33,859
Step-by-step explanation:
Given:
Sequence = 685+678+671+664+...+6
Find:
Sum of the sequence (Sn)
Computation:
a = 685
d = 678 - 985 = -7
an = 6
an = a+(n-1)d
6 = 685+(n-1)(-7)
-679 = (n-1)(-7)
97 = n-1
n = 98
So,
Sum of the sequence (Sn) = (n/2)[a+an]
Sum of the sequence (Sn) = (98/2)[685+6]
Sum of the sequence (Sn) = (49)(691)
Sum of the sequence (Sn) = 33,859
Complete Question:
Triangle abc has the angle mesausres shown.
m<A = (2x)°
m<B = (5x)°
m<C = (11x)°
Which statement is true about the angles?
A. m<A = 20°
B. m<B = 60°
C. m<A and m<B are complementary
D. m<A + m<C = 120°
Answer:
A. m<A = 20°
Step-by-step explanation:
m<A + m<B + m<C = 180° (sum of interior angles of a triangle)
(substitution)
Solve for x. Add like terms.

Divide both sides by 18


Find the measure of each angle by substituting x = 10:
m<A = (2x)° = 2(10) = 20°
m<B = (5x)° = 5(10) = 50°
m<C = (11x)° = 11(10) = 110°
Therefore, the only true statement is:
A. m<A = 20°
Cindy needs to buy 8 packs of invitations.