Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer:
47.25 + 23.75 = 71
Step-by-step explanation:
D. y = 3x + 2
Check (-4, -10)
-10 = 3(-4) + 2
-10 = -12 + 2
-10 = -10 :)
Check (-3, -7)
-7 = 3(-3) + 2
-7 = -9 + 2
-7 = -7 :)
Check (-2, -4)
-4 = 3(-2) + 2
-4 = -6 + 2
-4 = -4 :)
Check (-1, -1)
-1 = 3(-1) + 2
-1 = -3 + 2
-1 = -1 :)
Check (0, 2)
2 = 3(0) + 2
2 = 0 + 2
2 = 2 :)
Answer:
1. number of data values
2. sum of data values
Step-by-step explanation:
Triangle Congruence Theorems
Use the triangle congruence theorems below to prove that two triangles are congruent if:
Three sides of one triangle are congruent to three sides of another triangle (SSS: side side side)
Two sides and the angle in between are congruent to the corresponding parts of another triangle (SAS: side angle side)
Two angles and the side in between are congruent to the corresponding parts of another triangle (ASA: angle side angle)
Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle (AAS: angle angle side)
The hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle (HL: hypotenuse leg)
