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melamori03 [73]
3 years ago
10

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will e

ventually commit a crime. The government is deciding whether to rely on the clairvoyant Precogs to stop the criminals before they commit the crime. If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time (in other words, the Precogs fail to predict crime only in 0.001% of the cases). If a person is not going to commit a crime, the Precogs identify that person as law-abiding 99.99% of the times (in other words, the Precogs convict innocent people only in 0.01% of the cases). What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime
Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Flagged as future criminal

Event B: Commits a crime.

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will eventually commit a crime.

This means that P(B) = \frac{100}{1000100} = 0.00009999

If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time

This means that P(A|B) = 0.99999

Probability of being identified as a criminal:

0.99999 out of 0.00009999(identified and commits crime).

(1-0.99999) out of (1-0.00009999) (identifed and does not commits crime). So

P(A) = 0.99999*0.00009999 + (1-0.99999)*(1-0.00009999) = 0.000109988

What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.00009999*0.99999}{0.000109988} = 0.9091

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

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Find three consecutive odd integers such that three times the square of the first integer is twelve more than the product of the
7nadin3 [17]
Consecutive odd integers are 2 apart
they are
n,n+2,n+4


3(n²)=12+(n+2)(n+4)
expand
3n²=12+n²+6n+8
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minus n² both sides
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divide bot sides by 2
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3 years ago
Where is the intersection of the perpendicular<br> bisector of GF and the angle bisector of ZE?
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The intersection of the perpendicular bisector of GF and the angle bisector of ZE inside the quadrilateral.

What is a quadrilateral?

quadrilateral is a plane mathematical closed figure consist of four side and four edges. There are 7 types of quadrilateral

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d) Rhombus,

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as the given figure is unknown with dimension it is difficult to find the measurement but it is be to noted that the perpendicular bisector of GF and angle bisector of angle E will intersect at some point inside the given quadrilateral.

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2 years ago
What’s the answer please
skad [1K]

Answer:

h  ≤ 124 / 9

or

h  ≤ 13.78

Step-by-step explanation:

(3/4) (12h - 32) ≤ 100      (multiply both sides by 4)

(3) (12h - 32) ≤ 100 (4)

(3) (12h - 32) ≤ 400   (distribute 3 into the parenthesis)

(12h)(3) - (32)(3) ≤ 400   (expand left side terms)

36h - 96 ≤ 400   (add 96 to both sides)

36h  ≤ 400  + 96

36h  ≤ 496  (divide both sides by 36)

h  ≤ 496 / 36   (sinmplify)

h  ≤ 124 / 9

or

h  ≤ 13.78

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Let's solve your equation step-by-step.

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Step 1: Factor left side of equation.

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Step 2: Set factors equal to 0.
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For this one add one on both sides
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