Answer:
answer is 5.50
Step-by-step explanation:
multiply 2.75 times two because 3 by 5 is half of 9 by 15
Answer: (4, -9)
<u>Step-by-step explanation:</u>
Use elimination method. Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable. <em>I will be eliminating y</em>
6x + y = 15 → 2(6x + y = 15) → 12x + 2y = 30
-7x - 2y = -10 → 1(-7x + 2y = -10) → <u> -7x - 2y = -10</u>
5x = 20
x = 4
Next, replace "x" with "4" into either equation and solve for y.
6(4) + y = 15
24 + y = 15
y = -9
<u>Check:</u>
Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.
-7x - 2y = -10
-7(4) - 2(-9) = -10
-28 - -18 = -10
-28 + 18 = -10
-10 = -10 
Answer:
la probabilidad es 1/11
Step-by-step explanation:
Hay 4+4+4 = 12 canicas en total en la bolsa.
Pues la posibilidad de sacar una canica azul en el principio es 4/12 o 1/3.
Y luego, no reemplaces la canica, y hay 11 canicas en total.
Por eso la posibilidad de sacar otra canica azul después es 3/11.
Son eventos independientes, y tenemos que multiplicarlos para tener la respuesta.
1/3 * 3/11 = 1/11
Answer:
Refexive I think
Step-by-step explanation:
5(3) = 3(5)
or
x(y) = y(x)
I found this
"Anything equals itself: this is the "reflexive" (reflecting onto itself) property. Also, it doesn't matter which order the equality is in; if x = y, then y = x: this is the "symmetric" (they match) property."
Answer:
Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Step-by-step explanation:
Given:
First 4 test scores = 87%, 92%, 76%,89%
Average targeted = 80%
We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.
Solution:
Let the minimum score she needs to make in fifth test be 'x'.
Total number of test = 5
Now we know that;
Average is equal to sum of all the scores in the test divided by number of test.
framing in equation form we get;

Multiplying both side by 5 we get;

Subtracting both side by 344 we get;

Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.