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Artyom0805 [142]
3 years ago
10

Define a function in Scheme (or relation in Prolog) that checks whether a set of elements (represented as a list) is a subset of

another set (represented as a list).
Computers and Technology
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

subset([],[]).

       subset([X|L],[X|S]) :-

           subset(L,S).

       subset(L, [_|S]) :-

           subset(L,S).

Success:

     subset([1,3], [1,2,3]).

     subset(X, [1,3,4]).        % error handling to compare sets in a given order

Fail:

     subset([2,1], [1,2,3]).   % compares in a different order from the first.

Explanation:

The function "Subset" in the source code above accepts two sets, then checks if the first set is a subset of the second. The code returns true if the condition is met.

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You receive a phone call from a co-worker telling you that "the network is down." Just as you are about to look into the issue,
Dvinal [7]

This issue will happen mostly if cellular network will not be down, or suppose if cellular network is down mostly, or it will be rainy or a current cutoff issue might be occurred.

<u>Explanation:</u>

The following step to be made for trouble shoot his phone when cellular network is down.

1. Restart the mobile:- After restarting kindly check mobile connectivity.

2. Check for mobile air plane mobile and make sure the mobile phone is not in air plane mode.

3. Check the income and outgoing vapidity.

4. Switch off the mobile, Remove service provider sim card from mobile and reinsert the sim card and start the mobile.

5. Still connectivity problem, either contact the service provider or replace with new sim card.

5 0
3 years ago
JAVA
avanturin [10]

Answer:

   public ArrayList onlyBlue(String[] clothes){

       ArrayList<String> blueCloths = new ArrayList<>();

       for(int i =0; i<clothes.length; i++){

           if(clothes[i].equalsIgnoreCase("blue")){

               blueCloths.add(clothes[i]);

           }

       }

       return blueCloths;

   }

Explanation:

  • Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
  • Within the method body, create and initialize an Arraylist
  • Use a for loop to iterate the Array of cloths.
  • Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
  • Finally return the arrayList to the caller
3 0
3 years ago
Assume that minutes is an int variable whose value is 0 or positive. Write an expression whose value is "undercooked" or "soft-b
e-lub [12.9K]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {

     Scanner scan = new Scanner(System.in);

     System.out.println("Enter your minute:");

     int minute = scan.nextInt();

     

     switch(minute){

         case 0:

         case 1:

             System.out.println("undercooked");

             break;

         case 2:

         case 3:

         case 4:

             System.out.println("soft-boiled");

             break;

         case 5:

         case 6:

         case 7:

             System.out.println("medium-boiled");

             break;

         case 8:

         case 9:

         case 10:

         case 11:

             System.out.println("hard-boiled");

             break;

         case 12:

             System.out.println("overcooked");

             break;

         default:

             if(minute > 12){

               System.out.println("overcooked");

             } else if (minute < 0){

                 System.out.println("Enter a valid minute.");

             }            

     }

   }

}

Explanation:

The first line is the import statement, which import the Scanner class for receiving user input. The next line is the class declaration which is named Solution.

The Scanner object is declared and assigned as scan. Then a prompt is displayed to the user asking the user to enter the minute. The user input is stored as minute.

Switch statement is use to categorize the user input. If the user enter 0-1, an output of undercooked is displayed. If the user enter 2-4, an output of soft-boiled is displayed. If the user enter 5-7, an output of medium-boiled is displayed. If the user enter 12 or any number above 12, an output of overcooked is displayed. Again, the user enter a number less than zero, an error message is displayed telling the user to enter a valid number.

4 0
3 years ago
Caden, Jacob, Lucas, and Michael, whose last names are Armstrong, Boothe, Gardner, and Robinson, live in four houses in a row.
Anit [1.1K]

Answer:

Jacob Gardner - Lucas Robinson - Caden Boothe - Michael Armstrong

Explanation:

According to clue 4, Lucas's house is not the first, and he has a house on his right, so it can only be house 2 or house 3. Therefore, Caden's house (which is on the right right of Lucas's), it can only be house 3 or house 4.

In turn, track 1 says that Michael's house is not next to Lucas's, so it can be 1 (if Lucas's house is 3) or 4 (if Lucas's house is in 2).

Track 2 says that there is a house before Michael's, which eliminates the possibility that Michael's house is number 1 (there would be no previous house). Thus, in addition, Lucas's house turns out to be 2 (Michael's house is not next door) and Caden's is 3, while Jacon's is house 1.

Jacob - Lucas - Caden - Michael

In turn, regarding surnames, clue 2 says that Robinson's house is after Gardner's and before Michael's. Thus, Robinson can be the last name of Jacob or Lucas, and Gardner that of Lucas or Caden. Now, since Boothe's house is just before Armstrong's, the order would be as follows:

Jacob Gardner - Lucas Robinson - Caden Boothe - Michael Armstrong

4 0
3 years ago
Characteristic of first generation computer<br>​
ella [17]

Characteristics

based on vaccum tubes

they were large,slow,low capacity

Magnetic drums for primary memory

used mll

input punched cards and output printsout

expensive

get heated faster

eg. ENIAC,UNIVAC

6 0
3 years ago
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