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3 years ago

Y = 2x + 1 y = 3x - 1

Mathematics

2 answers:

yuradex [85]3 years ago

6 0

Answer:

i think the answer is B

Step-by-step explanation:

5=6-1

5=5

drek231 [11]3 years ago

5 0

just need to get the equations equal together then solve for x which will give u the x-coordinate of intersection then u need to put it in which equation u want to find the y-coordinate of intersection point :

2x + 1 = 3x - 1

Add both sides 1

2x + 1 + 1 = 3x - 1 + 1

2x + 2 = 3x

Subtract both sides 2x

2x - 2x + 2 = 3x - 2x

x = 2

( This is the x-coordinate of intersection point )

_________________________________

Now to find the y-coordinate of the intersection point we have to put the value of x we found in of the equations :

y = 2x + 1

y = 2(2) + 1

y = 4 + 1

y = 5

_________________________________

Thus :

intersection point = ( 2 , 5 )

So the correct answer is option B .

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Fittoniya [83]

The equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are as follows:

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Equations 4x = 32,000 4y = 24,000

<h3>What is an equation?</h3>

An equation is a mathematical statement that shows the values of two mathematical expressions are equal.

An equation is made up of two mathematical expressions connected by an equal sign.

<h3>Data and Calculations:</h3>

Annual expenses for lion per unit, x = $8,000

Annual expenses for leopard per unit, y = $6,000

Total number of larget-cats required = 8

Let the cost of maintaining 4 lions = 4x

Let the cost of maintaining 4 leopards = 4y

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Total cost for 4 leopards = $24,000 (6,000 x 4)

Total cost for eight large cats per year = $56,000 ($32,000 + $24,000)

Equation for lions, 4x = 32,000

Equation for leopards, 4y = 24,000

The total costs for maintaining eight large cats in all will be <u>$56,000</u> per year.

Thus, the equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are <u>4x = 32,000</u> and <u>4y = 24,000</u>, respectively.

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2 years ago

Solve question 3 for <br> 41 points

Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: $ln(\frac{\sqrt{e} }{y^3} )$ .

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

$ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)$

Also, we can write square roots as powers of one-half, so √e = $e^{1/2}$ . There's another log property that: $ln(a^b)=b*ln(a)$ . We can apply that here for both the √e and the y³:

$ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)$

Finally, note that ln(e) is just 1, so we have:

$\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}$

The answer is thus (2).

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3 years ago

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Arturiano [62]

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Step-by-step explanation:
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ElenaW [278]

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