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lawyer [7]
3 years ago
12

Y = 2x + 1 y = 3x - 1

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer:

i think the answer is B

Step-by-step explanation:

5=6-1

5=5

drek231 [11]3 years ago
5 0

just need to get the equations equal together then solve for x which will give u the x-coordinate of intersection then u need to put it in which equation u want to find the y-coordinate of intersection point :

2x + 1 = 3x - 1

Add both sides 1

2x + 1 + 1 = 3x - 1 + 1

2x + 2 = 3x

Subtract both sides 2x

2x - 2x + 2 = 3x - 2x

x = 2

( This is the x-coordinate of intersection point )

_________________________________

Now to find the y-coordinate of the intersection point we have to put the value of x we found in of the equations :

y = 2x + 1

y = 2(2) + 1

y = 4 + 1

y = 5

_________________________________

Thus :

intersection point = ( 2 , 5 )

So the correct answer is option B .

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1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th
Kryger [21]

Answer:

a

  P = 0  OR  P = 135

b

P > 0 and P < 135

OR

P > 0 and P < 135

c

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

d

P = 67.5

Step-by-step explanation:

From the question we are told that

The population model is \frac{dP}{dt}  =  0.2P(1 - \frac{P}{135} )

Generally at equilibrium

\frac{dP}{dt} = 0

So

0.2P = 0

=> P = 0

Or

(1 - \frac{P}{135} ) = 0

=> P = 135

Thus at equilibrium P = 0 or P = 135

Generally when the population is increasing we have that

\frac{dP}{dt} > 0

So

0.2P > 0

=> P > 0

and

(1 - \frac{P}{135} ) > 0

P < 135

Now when the first value of P i.e P< 0 for \frac{dP}{dt} > 0

P_2 > 135

So when population increasing the values of P are

P > 0 and P < 135

OR

P > 0 and P < 135

So to obtain initial values of P where the population converge to the carrying capacity as t \to [\infty]

The rate equation can be represented as

\frac{dP}{dt}  =  \frac{1}{5}P (1 - \frac{P}{135} )

So we will differentiate the equation again we have that

\frac{d^2 P}{dt^2} = \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675}

Now as  t \to [\infty]

\frac{d^2 P}{dt^2} \to  0

So

   \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675} = 0      

=>    \frac{(1 - \frac{P}{135} )}{5}   =  \frac{P}{675}

=> P = 67.5

5 0
3 years ago
2. The product of an even number and an odd number is an even number.
ASHA 777 [7]

Answer:

5

Step-by-step explanation:

ok thanks

4 0
3 years ago
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If a=3 and b=5, find a<br> -<br> b
Keith_Richards [23]

Answer:

-2

Step-by-step explanation:

3-5 = -2

3-> a

5 -> b

4 0
3 years ago
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