Using sampling concepts, it is found that the correct option regarding if this is a random sample is given by:
Yes, because the slips of paper were all the same shape and size.
<h3>How are samples classified?</h3>
Samples may be classified as:
- Convenient: Drawn from a conveniently available pool.
- Random: All the options into a hat and drawn some of them.
- Systematic: Every kth element is taken.
- Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
- Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.
In this problem, since the slips have the same shape and size, each name has an equal probability of being chosen, hence it is a random sample and the correct option is:
Yes, because the slips of paper were all the same shape and size.
More can be learned about sampling concepts at brainly.com/question/25122507
Answer:
Step-by-step explanation:
it is too easy use your calculator!(-_-メ)
Answer:
The fourth option gives the result.
Step-by-step explanation:
We have to find f(x) and g(x) from options given such that y = f[g(x)] is equivalent to 
.
Here, the fourth option gives the result.
If 
and g(x) = 2x + 4, then the composite function ![f[g(x)] = \frac{8}{\sqrt{2x + 4}}](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%20%3D%20%5Cfrac%7B8%7D%7B%5Csqrt%7B2x%20%2B%204%7D%7D)
⇒ 
( Answer )
Answer:
The answer is B (AKA) 102
Step-by-step explanation:
180-78
one angle is 180 degrees
Answer:
Step-by-step explanation:
Proportion of retired people under the age of 65 would return to work on a full-time basis if a suitable job were available = 60/100 = 0.6 = P
Null hypothesis: P ≤ 0.6
Alternative: P > 0.6
First, to calculate the hypothesis test, lets workout the standard deviation
SD = √[ P x ( 1 - P ) / n ]
where P = 0.6, 1 - P = 0.4, n = 500
SD = √[ (0.6 x 0.4) / 500]
SD = √ (0.24 / 500)
SD = √0.00048
SD = 0.022
To calculate for the test statistic, we have:
z = (p - P) / σ where p = 315/500 = 0.63, P = 0.6, σ = 0.022
z = (0.63 - 0.6) / 0.022
z = 0.03/0.022
z = 1.36
At the 2% level of significance, the p value is less than 98% confidence level, thus we reject the null hypothesis and conclude that more than 60% would return to work.
