Question

" {x}^{2} + 2x = 0" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$\textbf{Hello!}$

$\Longrightarrow2^2+2z=0$

$\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}$

$\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}$

$\Longrightarrow =\sqrt{2^2-0}$

$\Longrightarrow =\sqrt{2^2}$

$\Longrightarrow=2$

$\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}$

$\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}$

$\Longrightarrow\frac{-2+2}{2\cdot \:1}$

$\Longrightarrow =\frac{0}{2\cdot \:1}$

$\Longrightarrow =\frac{0}{2}$

$=0$

$\Longrightarrow\frac{-2-2}{2\cdot \:1}$

$\Longrightarrow =\frac{-4}{2\cdot \:1}$

$\Longrightarrow =\frac{-4}{2}$

$\Longrightarrow =-\frac{4}{2}$

$=-2$

$x=0,\:x=-2\Longleftarrow$

$\underline{HOPE ~IT~HELPS}$