Answer:
-101
Step-by-step explanation:
cuz in all the negative integers the small number is the bigger number
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
1st angle = 2 * 2nd angle
3rd angle = 2nd angle + 80
1st angle = 2x
2nd angle = x
3rd angle = 80 + x
2x + x + 80 + x = 180
4x = 100
x = 25
1st angle = 50
2nd angle = 25
3rd angle = 105
I’m going to say the top one it seems like that would be correct
Answer:
7x
Step-by-step explanation:
It equals 28 just like the problem with parentheses, 7x .