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3 years ago

What is the range of the following function?

Mathematics

1 answer:

ankoles [38]3 years ago

4 0

Answer:

-4 ≤ y < ∞

Step-by-step explanation:

The graph shows the range (vertical extent) has a minimum value of -4, and includes all y-values greater than or equal to that value.

In interval notation, the range is [-4, ∞).

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Write you answer in the simplest terms

crimeas [40]

Answer:

Step-by-step explanation:

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3 years ago

What is the congruence method you will use to show that the triangles are congruent?

kozerog [31]

The answer would be SSS or Side-Side-Side.

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2 years ago

Read 2 more answers

B is the midpoint of AC. AB= 3(3x-1) and AC=5(2x+2) find X, AB, BC, and AC

VMariaS [17]

Answer:

x = 2

Step-by-step explanation:

AB is given as 3(3x-1) multiply inside the parenthesis with 3

AB = 9x - 3

AC is given as 5(2x+2) multiply inside the parenthesis with 5

AC = 10x + 10

if B is midpoint of AC then AB = BC and AC = AB + BC if we write this equation using the given values

9x - 3 + 9x - 3 = 10x + 10 add like terms

18x - 6 = 10x + 10 transfer like terms to the same side of the equation

18x - 10x = 10 + 6

8x = 16 divide both sides by 8

x = 2 replace x with 2 in given expressions to find the value of each component

4 0

1 year ago

Read 2 more answers

Find the total surface area of this triangular prism.

Irina18 [472]

Answer:

not sure but i think its 425 cm

Step-by-step explanation:

for the square i dont know

how its called in english the surface is 25×10= 250cm

and for the triangle its (25×14):2 = 175cm

so 175 + 250= 425cm

4 0

2 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago