<span>y = mx + b</span><span>
m = slope = 2
b = y intercept = -6
</span>
<span>I am hoping that
this answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.</span>
<span>
</span>
Answer:
So that's actually not true. When comparing decimals you should compare each digit. Remember adding a 0 at the end does not change the value of the decimal. So lets look at it up and down:
remember line up the decimal to decimal
<u>1</u>.628
<u>1</u>.630
the first digit is the same. Both of these numbers are also before the decimal.
let's look at the second digit.
1.<u>6</u>28
1.<u>6</u>30
they are also the same. Both of these are also right after the decimal point.
now let's look at the third digit.
1.6<u>2</u>8
1.6<u>3</u>0
In this case, the bottom number has a higher value. Since 3>2, the bottom number is the overall biggest. Or you could look at it and say "Oh! 30 is bigger than 28!" I hope this helps you, and if this wasn't what you were looking for, oops
Answer:
join what?
Step-by-step explanation:
To solve the problem shown above you must apply the following proccedure:
1. Let's call:
x: a number.
f: the factor.
2. Then, you have:
√fx=3√x
3. You must clear the factor "f" to calculate its value, as below:
√fx=3√x
(√fx)²=(3√x)²
fx=9x
f=9x/x
4. Then, the factor is:
f=9
5. Therefore, b<span>y what factor must you multiply a number in order to triple its square root?
</span>
The answer is: 9
now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus 
.
so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.
![\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bsum%20of%20a%20finite%20geometric%20sequence%7D%5C%5C%5C%5CS_n%3D%5Csum%5Climits_%7Bi%3D1%7D%5E%7Bn%7D%5C%20a_1%5Ccdot%20r%5E%7Bi-1%7D%5Cimplies%20S_n%3Da_1%5Cleft%28%20%5Ccfrac%7B1-r%5En%7D%7B1-r%7D%20%5Cright%29%5Cquad%20%5Cbegin%7Bcases%7Dn%3Dn%5E%7Bth%7D%5C%20term%5C%5Ca_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5Cr%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C----------%5C%5Ca_1%3D2000%5C%5Cr%3D1.1%5C%5Cn%3D4%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5CS_4%3D2000%5Cleft%5B%20%5Ccfrac%7B1-%281.1%29%5E4%7D%7B1-1.1%7D%20%5Cright%5D%5Cimplies%20S_4%3D2000%5Cleft%28%5Ccfrac%7B-0.4641%7D%7B-0.1%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_4%3D2000%284.641%29%5Cimplies%20S_4%3D9282%20)
