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Over [174]
3 years ago
8

Given the function g(x) = x^3 − (8+1)x^2-4(9+2)x+(5x2-1) determine where the function is quickly(slowly) increasing (decreasing)

Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

hence g(x) is increasing at point x= 3+14i,3-14i

Step-by-step explanation:

given, g(x)=x^3-(8+1)x^2-4(9+2)x+5x2-1

         g(x)=x^3-9x^2-44x+10x-1

         g(x)=x^3-9x^2-34x-1

   \frac{\partial g(x)}{\partial x}=3x^2-18x-34

for increasing and decreasing function,

3x^2-18x-34=0

x=3+14i \geq0

x=3-14i \geq0

hence g(x) is increasing at point x= 3+14i,3-14i answer

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2 years ago
How do I solve question 6 through 8?<br> Solve for me
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The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

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<u>Question #7</u>

The vertex of the graph is

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So, we have:

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The graph pass through (1, 3)

So, we have:

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Evaluate the like terms

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y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

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So, we have:

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Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

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5 0
1 year ago
543,982 rounded to the nearest hundred thousand
Bezzdna [24]

Hello! :)

543,982 rounded to the nearest hundred thousand would be 500,000. Because the digit 4 is less than 5, it would be 600,000. If the digit where the 4 is was 5 or more, it would round to 600,000,

543,982 to the nearest hundred is 500,000.

Hope this helped you!

THEDIPER

3 0
3 years ago
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