Given the function g(x) = x^3 − (8+1)x^2-4(9+2)x+(5x2-1) determine where the function is quickly(slowly) increasing (decreasing)
1 answer:
Answer:
hence g(x) is increasing at point x= 3+14i,3-14i
Step-by-step explanation:
given, g(x)=x^3-(8+1)x^2-4(9+2)x+5x2-1
g(x)=x^3-9x^2-44x+10x-1
g(x)=x^3-9x^2-34x-1
=3x^2-18x-34
for increasing and decreasing function,
3x^2-18x-34=0
x=3+14i 0
x=3-14i 0
hence g(x) is increasing at point x= 3+14i,3-14i answer
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By applying Segment Addition Postulate, segment FH is equal to 24 units.
<h3>What is a point?</h3>A point can be defined as a zero dimensional geometric object and it is generally represented by a dot.
<h3>What is a line segment?</h3>A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.
<u>Given the following data:</u>
- Line segment FG = 37.
- Segment HG = 13.
Since point H lies on line segment FG, we would apply Segment Addition Postulate to determine segment FH as follows:
FG = HG + FH
37 = 13 + FH
FH = 37 - 13
FH = 24 units.
Read more on line segment here: brainly.com/question/17617628
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Complete Question:
Given that line segment FG = 37 and segment HG = 13, find segment FH.
