Anyone want to help me with my math assignments ill post another question with the assignments on it

Figure ABC is to be translated to Figure A'B'C' using the rule (x, y) → (x−2, y+3). Triangle ABC on the coordinate plane with th

Gelneren [198K]

( 0, 8 ) → B

Apply the given rule to the coordinates of point B (2, 5 )

thus B' = ( 2 - 2, 5 + 3 ) = (0, 8 )

8 0

3 years ago

Hailey is considering taking out an 8-year loan with monthly payments of $115 at an APR of 3.2%, compounded monthly, and this eq

vova2212 [387]

The answer is D -- Apex

5 0

3 years ago

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The income tax policy for residents of a tiny island nation that uses U.S. Dollars as its currency is as follows: The first $20,

Stells [14]

Answer:

C.

0.10(20,000) + 0.18(30,000) + 0.27(x − 50,000)

Step-by-step explanation:

Let's take this one step at a time. First, the $20000 dollars is taxed by 10% = .10 as a decimal. So the first term is

.10(20000)

Next, we have to add on the second term, wherein the next $30000 is taxed by .18. So the second term is

.10(20000) + .18(30000)

Then, we have to take whatever's left, whatever we haven't yet taxed, and tax it at a 27% rate. This means x-50000, not x, because we're taking whatever's over the initial 50000 that we've already taxed.

0.10(20,000) + 0.18(30,000) + 0.27(x − 50,000)

5 0

2 years ago

Solve for x in the equation x squared minus 4 x minus 9 = 29. x = 2 plus-or-minus StartRoot 42 EndRoot x = 2 plus-or-minus Start

Furkat [3]

Answer:

$x=2$\pm$\sqrt{42}$

Step-by-step explanation:

The given equation is:

$x^{2} -4x-9=29\\\Rightarrow x^{2} -4x-9-29=0\\\Rightarrow x^{2} -4x-38=0$

Formula:

A quadratic equation $ax^{2} +bx+c=0$ has the following roots:

$x=\dfrac{-b+\sqrt D}{2a}\ and\\x=\dfrac{-b-\sqrt D}{2a}$

Where $D= b^{2} -4ac$

Comparing the equation with $ax^{2} +bx+c=0$

a = 1

b = -4

c= -38

Calculating D,

$D= (-4)^{2} -4(1)(-38)\\\Rightarrow D = 16+152 = 168$

Now, finding the roots:

$x=\dfrac{-(-4)+\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4+2\sqrt {42}}{2}\\\Rightarrow x=2+\sqrt {42}\\and\\x=\dfrac{-(-4)-\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4-2\sqrt {42}}{2}\\\Rightarrow x=2-\sqrt {42}$

So, the solution is:

$x=2$\pm$\sqrt{42}$

5 0

2 years ago

Any number in the form of a ± bi , where a and b are real numbers and b 0 is considered a pure imaginary number.

Stella [2.4K]

Answer.
1) False
2) False
3) False

Explanation
1) When a number is written as a+bi, a and b are real number. b is never considered as imaginary number.
The statement given is false.

2) The value of i is √(-1), when squared we get;

(√(-1))² = -1.
The answer given is false.

3) It is not possible to graph a complex number is XY coordinates. Complex number are graphed on an imaginary axis and real axis only.
The statement given is false.

7 0

3 years ago

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