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1 year ago

6/(v+4) + 2/(v-6) What is the answer?

Mathematics

1 answer:

laiz [17]1 year ago

5 0

Answer:

8v-28/v^2-2v-24

Step-by-step explanation:

1. Find common denominator

2. Combine fractions with common denominator

3. Re-order terms so constants are on the left

You might be interested in

Can you help me find x

kifflom [539]

X = 30

hope that helps

180 - 108 = 72

180 - 72 -43 = 65

triangle on the left
Angles = 43,65,72

triangle on the right

180 - 65 = 115

180 - 115 - 35 = 30
so angles of triangle on the right = 30, 35, 115

x = 30 (vertical angles with the other angle of triangle on the right)

7 0

3 years ago

Savings account with 200$ and receive 4% interest for 7 years, how much would be in the account?

Fantom [35]

Answer:

256

Step-by-step explanation:

To calculate these kinds of things, I multiply the principal (200), the interest rate (0.04) and the time (7). This results in 56. However, since the question is how much would be in the account, it would be 200+56 which is 256.

5 0

3 years ago

The rectangular coordinates of a point are given. Find the polar coordinates (r,theta) of this point with theta expressed in r

alexandr402 [8]

Answer:}

In polar coordinates P is

P ( 12 ; 2.618 )

Step-by-step explanation:

The point (ectangular coordinates)

P ( -6√3 ; 6 ) P ( x ; y )

Polar coordinates P ( r ; θ )

x = r cos θ

y = r sin θ r > 0 and 0 ≤ θ ≤ 2π

Then

r = √ (x)² + (y)² r = √(36)²*3 +( 36)² r = √144

r = 12 (hypothenuse module always positive)

The point P ( -6√3 ; 6 ) is in second cuadrant between 90° and 180°

angle between r and horizontal axis x is equal to θ

tan α = l.opp/ l.adj. tan θ = y/x tan θ = - 6 /6√3

tan α = - 1/√3

Then α = 180⁰ - 150⁰ = 30⁰ or θ = 150⁰

to express that value in radians we have :

1 π radian = 180⁰ ⇒ 3,1416 radians = 180⁰

x ?? = 150⁰

x = radians

Finally the point is P ( 12 ; 2.618 )

6 0

3 years ago

Write an equation perpendicular to the x axis and contains the points (9,-2)

uranmaximum [27]

X=9
so simple
it's vertical line

3 0

2 years ago

From the lighthouse 1000 ft above sea level the angle of depression to boat a is 29 degress.a little bit later the boat moved cl

AnnyKZ [126]

Answer: The boat moved 768.51 feet in that time .

Step-by-step explanation:

Since we have given that

Height of the lighthouse = 1000 feet

Angle depression to boat 'a' = 29°

Angle of depression to shore 'b' = 44°

Consider ΔABC,

$\tan 44\textdegree=\frac{AB}{BC}\\\\\tan 44\textdegree=\frac{1000}{BC}\\\\BC=\frac{1000}{\tan 44\textdegree}\\\\BC=1035.53\ feet$

Now, Consider, ΔABD,

$\tan 29\textdegree=\frac{AB}{BD}\\\\\tan 29\textdegree=\frac{1000}{BD}\\\\BD=\frac{1000}{\tan 29\textdegree}\\\\BD=1804.04\ feet$

We need to find the distance that the boat moved in that time i.e. BC

so,

$DC=BD-BC\\\\CD=1804.04-1035.53\\\\CD=768.51\ feet$

Hence, the boat moved 768.51 feet in that time .

6 0

3 years ago