A six-sided die is rolled ten times. What is the probability that the die will show an even number at most eight times?
1 answer:
P(even)=1/2. P(odd)=1/2. Let x= number of even in ten rolls
P(x<=8) = 1-P(x>=9) = 1-[C(10,9)(1/2)^9 *(1/2)^1 + C(10,10)(1/2)*(1/2)^0]
=1-[C(10,9)(1/2)^10 +C(10,10)(1/2)^10]
=1-(1/2)^10[10+1
=1–11/1024
=1013/1024
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